Answer:
(1) The correct option is (A).
(2) The probability that Aadi will get Tails is
.
Step-by-step explanation:
It is provided that:
- Eric throws a biased coin 10 times. He gets 3 tails.
- Sue throw the same coin 50 times. She gets 20 tails.
The probability of tail in both cases is:
(1)
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
In this case we need to compute the proportion of tails.
Then according to the Central limit theorem, Sue's estimate is best because she throws it <em>n = </em>50 > 30 times.
Thus, the correct option is (A).
(2)
As explained in the first part that Sue's estimate is best for getting a tail, the probability that Aadi will get Tails when he tosses the coin once is:

Thus, the probability that Aadi will get Tails is
.
Answer:
no clue but good luck bro
Step-by-step explanation:
7(x + 2) = 6(x + 5)
7x + 14 = 6x + 30 |subtract 14 from both sides
7x = 6x + 16 |subtract 6x from both sides
x = 16
20 total marbles....7 are green
probability on first draw is 7/20...and since the marble was not replaced, the probability on the second draw is 6/19. And since they cant happen at the same time, we multiply
7/20 * 6/19 = 42/380 which reduces to 21/190