Answer:
0.76%
Explanation:
Firstly we write out the production function to be
Y = K^0.34L^0.42.
So if we have inputs that are increased by 1%, we will now have a new production function which is
Y = (K + 0.01 of K)^0.34 (L + 0.01 of L)^0.42
We write this in terms of growth rate
The Growth rate of Y = 0.34 x the growth rate of K + 0.42 x the growth rate of L
This gives us the Growth rate of Y = 0.34 x 1% + 0.42 x 1%
= 0.34+0.42
= 0.76%
Answer:P value = 1 - 0.9793 = 0.0207
Explanation:
we can use Z value and normal distribution to find P value. P value is the area of beyond the value of Z value
sample mean (x.bar) = $52.20
Population mean (U) = $50
Sample Standard deviation (Sd) =$ 6.10
sample (n) = 25
Z =
=
Z = 2.50/1.22 = 2.049280328 = 2.049
area (normal distribution table) = 0.9793
P value = 1 - 0.9793 = 0.0207
Answer:
31 December 2019
Cash 19000 Dr
Accumulated depreciation 12186 Dr
Equipment 27419 Cr
Gain on disposal 3767 Cr
Explanation:
Straight line depreciation method charges a constant depreciation expense through out the useful life of the asset.
To calculate the gain or loss on disposal/sale of an asset like this, we need to first determine the book value or carrying value of asset on that day.
Carrying value = Cost - Accumulated depreciation
Carrying value = 27419 - 12186
Carrying value = $15233
Gain or (loss) on disposal = Cash/Sale proceeds - Carrying Value
Gain or (loss) on disposal = 19000 - 15233
Gain or (loss) on disposal = $3767 Gain
The answer is selecting an alternative. It is because it is
not always satisfying or a guarantee of using an alternative in the stage of
managerial decision making process because sometimes it won’t suit or will be
helpful in solving the problem.
Though I have no experience in business, I would say it is True.