In order to achieve an equilibrium some of momentum should be zero about the axis of rotation.
Suppose, the 10-kilogram child is placed X meters away from the axis of rotation.
Now, according to the question
17x2+10X-20x2=0
X=0.6m
Child should sit 0.6m away from the axis of rotation towards 17 Kg child.
Answer:
0.61 or 8.79
Step-by-step explanation:
h = 47t − 5t²
27 = 47t − 5t²
5t² − 47t + 27 = 0
Quadratic formula:
t = [ -b ± √(b² − 4ac) ] / 2a
t = [ -(-47) ± √((-47)² − 4(5)(27)) ] / 2(5)
t = (47 ± √1669) / 10
t ≈ 0.61 or 8.79
Answer:
1 month
Step-by-step explanation:
249 is the amount she spends for buying the kitten, (299-50=249) which she only has to pay once.
20 is the amount she has to spend every month, the rate of change.
The problem can be modeled with the general equation:
y = 20x + 249
In this equation, x the the time in months and y is the amount of money spent.
Substitute 250 for y.
y = 20x + 249
250 = 20x + 249 <= isolate x to get the number of months
1 = 20x
x = 1/20
Carol will only spent money every month, not for 1/20 of a month.
It will only take Carol 1 month to spent $250.
Check answer:
Substitute x for 1
y = 20x + 249
y = 20(1) + 249
y = 269
269 is more than 250 already.
