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inessss [21]
3 years ago
15

Answer please for x and y

Mathematics
1 answer:
notsponge [240]3 years ago
7 0
Add the equations together:
12x-12x-11y-5y=40+88
you get
-16y=128
divide y=128/-16
y=-8

then plug-8 for y back into either equation.
12x-11(-8)=88
12x+88=88
12x=0
x=0
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Y=|4x|-1 what is the absolute value
maks197457 [2]

Answer:

-1

Step-by-step explanation:

5 0
3 years ago
What is the solution to the system of equations <br><br> 3x+2y=39<br> 5x-y=13
Marta_Voda [28]

3x + 2y = 39

5x - y = 13

Multiplying the last by two:

10x - 2y = 26

Adding to the first

13x = 65

x = 5

y = 5x-13 =25-13=12


Check:

3(5)+2(12)=39 good

5(5)-12=13 good


Answer: x=5, y=12


8 0
3 years ago
Please help i have to turn in in 8 mins....thanks :)
pychu [463]

6√3

Step-by-step explanation:

6 is x. side across from right angle (12) is 2x. so 6x2 to get 12. missing side is x√3. so 6√3

6 0
3 years ago
Read 2 more answers
5. Consider the following equations.
WITCHER [35]

Answer:

Step-by-step explanation:

In y = mx + b form, the slope can be found in the m position and the y intercept can be found in the b position.

4x - 2y = -6

-2y = -4x- 6

y = (-4/-2)x -(6/-2)

y = 2x + 3....slope here is 2, and y int is 3

3x + y = 3

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3 0
3 years ago
Write the equation in the form Ax + By = C. Find an equation of a line passing through the pair of points (-7,3) and (-8,-9).
Illusion [34]

Answer:

  12x -y = -87

Step-by-step explanation:

You can start with the 2-point form of the equation of a line and manipulate it to give you the standard form.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  y = (-9 -3)/(-8 -(-7))(x -(-7)) +3

  y = (-12/-1)(x +7) +3

  y = 12x +84 +3

  -12x +y = 87 . . . . . subtract the x-term

  12x -y = -87 . . . . . . make the leading coefficient positive (per standard form)

3 0
3 years ago
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