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german
3 years ago
12

Will give brainliest!!!!!!!!!!!!!!!!!!!!!!!!!

Physics
2 answers:
marshall27 [118]3 years ago
8 0
1. I would advise this student to manage homework by doing it as soon as possible, like on the ride home, or even during free-time during school. I would never advise to put it off until the day it is due. They should also go over their homework a few times to retain new knowledge.
2. This student should take NEAT notes, and have organization as top priority. Notes should also be detailed to prevent confusion.
3. When reading, this student should NOT skim, you could miss vital information. You should also reread if you have time.
4. One last thing, when doing homework or reading, you should block out as much distractions as possible.

 Really hope this helps!!

earnstyle [38]3 years ago
5 0
Based on my own personal experience...

Definitely get your parents to buy you folders for each subject, including paper along with it. Write on the covers which to which, and manage from on there. Your stuff will be organized and easy to obtain.

Sticky notes can help with deadlines and overdues. They can be purchased or downloaded (your PC may already have them).

When you read a book, think about the most important thing that came into mind when you read it. Ask yourself questions like: "What was the Summary of this story? What did the main character(s) struggle with? What was the the conclusion or author wanted to be known from?" Because these questions are most likely going to be answered later on by quiz or textbook. You can also find audios elsewhere if you aren't a reader.

Get onto a schedule. If you don't already own a calendar, it's good to keep in track of your days and mornings. It is said that if you go to bed before 10PM, your body consumes your energy for the next day. Eat 30 minutes before your hungry, so you can have a head start and fresh mind.

These are few of the things that helped me (and still do). Most importantly, don't procrastinate. You'll feel overall better getting things finished and out of the way. Good luck.
You might be interested in
What average power must be supplied to the rope to generate sinusoidal waves that have amplitude 0.200 m and wavelength 0.600 m
pychu [463]

Complete question:

A taut rope has a mass of 0.123 kg and a length of 3.54 m. What average power must be supplied to the rope to generate sinusoidal waves that have amplitude 0.200 m and wavelength 0.600 m if the waves are to travel at 28.0 m/s ?

Answer:

The average power supplied to the rope to generate sinusoidal waves is 1676.159 watts.

Explanation:

Velocity = Frequency  X wavelength

V = Fλ ⇒ F = V/λ

F = 28/0.6 = 46.67 Hz

Angular frequency (ω) = 2πF = 2π (46.67) = 93.34π rad/s

Average power supplied to the rope will be calculated as follows

P_{avg} =\frac{1}{2} \mu \omega^2 A^2 V

where;

ω is the angular frequency

A is the amplitude

V is the velocity

μ is mass per unit length = 0.123/3.54 = 0.0348 kg/m

P_{avg} =\frac{1}{2} ( 0.0348)(93.34 \pi )^2 (0.2)^2 (28) = 1676.159 watts

The average power supplied to the rope to generate sinusoidal waves is 1676.159 watts.

6 0
3 years ago
A spring with a spring constant of 4 N/m is stretched by Sarah's dog until extended by 2 m. How much elastic potential energy is
azamat

Hi there!

Recall the equation for spring potential energy:

PE = \frac{1}{2}kx^2

k = Spring constant (N/m)

x = extension of spring from equilibrium (m)

PE = Potential Energy (J)

Plug in the given values:

PE = \frac{1}{2}(4)(2^2) = \boxed{8 J}

8 0
2 years ago
A ball is thrown vertically upwards at 19.6 m/s. for its complete trip (up and back down to the starting position), its average
Alex17521 [72]
The average velocity of an object is given by:
Average velocity = total displacement / total time

First, we calculate the time taken to reach the maximum height of the ball. This occurs when the final velocity is 0.
Vf = Vi + at
0 = 19.6 - 9.81 * t
t = 2 seconds

The total trip will be of 4 seconds (2 seconds up, 2 seconds down)

The total displacement is given by:
s = ut + 1/2 * at²
s = 19.6 * 2 - 0.5 * 9.81 * 2²
s = 19.6 meters

This is the distance maximum height, so the total height is
19.6 * 2 = 39.2 meters

Average velocity = 39.2 / 4
Average velocity = 9.8 m/s
5 0
3 years ago
Calculate the de Broglie wavelength of an electron traveling at 2.0 x 10^8 m/s (me = 9.1*10^-31 kg).
timofeeve [1]

Answer:

\lambda=3.64\times 10^{-12}\ m

Explanation:

We have,

Speed of an electron is 2\times 10^8\ m/s

It is required to find the De Broglie wavelength of electron. The formula for the De- Broglie wavelength is given by :

\lambda=\dfrac{h}{mv}

h is Planck's constant

m is mass of an electron

Plugging all the values we get :

\lambda=\dfrac{6.63\times 10^{-34}}{9.1\times 10^{-31}\times 2\times 10^{8}}\\\\\lambda=3.64\times 10^{-12}\ m

So, the De-Broglie wavelength of an electron is 3.64\times 10^{-12}\ m

4 0
3 years ago
Answer the following questions.
Marta_Voda [28]
It's the number of protons that are in an element
3 0
3 years ago
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