4 years ago

What are the typical properties of covalent substances ?

1 answer:

4 0

Covalent compounds are compounds that share electrons. They tend to have properties like lower melting points and lower conductivity.

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which one of these is caused by gravity? A. frost wedging. B. mass wasting. C. Aeolian bands. D. Glaciation

AlladinOne [14]

If I remember correctly, the answer is A

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4 years ago

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What is the mass of bromine gas if it has a pressure of 720 mmHg, volume of 25mL and a temperature of 18.3 degrees Celsius

Annette [7]

Answer:

Mass = 0.158 g

Explanation:

Formula used,

P V = n R T

Or,

n = P V / R T

Putting values,

n = 0.948 atm . 0.025 L / 0.0821 L.atm.K⁻¹.mol⁻¹ . 291.45

n = 0.00099 mol

Note: we have changed pressure from mmHg to atm, volume from mL to L and temperature from C to K)

Also,

Mass = n . Molecular Mass

Mass = 0.00099 mol × 159.808 g/mol

Mass = 0.158 g

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2 years ago

Kia is doing an experiment in science lab. She is given a beaker containing 100 g of liquid. The beaker has markings on the side

Semmy [17]

Kia's remaining water has a mass of 50g. You can set it up as a proportion knowing that 100ml of water has a mass of 100g and thus 50ml of water would weight 50g

7 0

3 years ago

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The molar mass of an unknown gas was measured by an effusion experiment. It was found that it took 60 s for the gas to effuse, w

Marizza181 [45]

Answer:

The molar mass of the gas is 44 g/mol

Explanation:

It is possible to solve this problem using Graham's law that says: Rates of effusion are inversely dependent on the square of the mass of each gas. That is:

$\frac{r_1}{r_2} =\frac{\sqrt{M_2} }{\sqrt{M_1} }$

If rate of effusion of nitrogen is Xdistance / 48s and for the unknown gas is X distance / 60s and mass of nitrogen gas is 28g/mol (N₂):

$\frac{X/48s}{X/60s} =\frac{\sqrt{M_2} }{\sqrt{28g/mol} }$

6,61 = √M₂

44g/mol = M₂

The molar mass of the gas is 44 g/mol

I hope it helps!

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3 years ago

Type of reaction PbSO. → PbSO3 + __02 Type of reaction:

Marysya12 [62]

Answer:

work out the mean mode median and range

Explanation:

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3 years ago