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sergejj [24]
3 years ago
9

Sulfur does not dissolve in water but it does dissolve in carbon disulfide

Chemistry
2 answers:
Aleks [24]3 years ago
8 0

Answer:

True.

Explanation:

Hello,

Solubility is strongly dependent on both solute's and solvent's polar nature, in such a way, since water is highly polar and sulfur is non-polar, a non-polar solvent must be used to dissolve it. In this case carbon disulfide is proposed, so the way to substantiate it is non-polar is via the difference in the electronegativity of the carbon and sulfur as shown below:

\Delta E=E_S-E_C\\\Delta E=2.58-2.55\\\Delta E=0.03

Since such difference is very close to zero making it a highly non-polar substance, consequently, sulfur will dissolve into it.

Best regards.

Lynna [10]3 years ago
3 0
It is really difficult to dissolve the sulfur substance because not only is it polar, but it is composed of long S-chains and not only atoms. So, water cannot dissolve the sulfur because nonpolar compounds do not dissolve in polar solvents. Sulfur doesn't always dissolve with nonpolar solvents, as well. However, since carbon disulfide also contains S-chains, it is the best solvent that would dissolve sulfur.
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The equations you need are moles = concentration x volume

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5 0
3 years ago
Show
SIZIF [17.4K]

Answer: 0.9375 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}     .....(1)

Molarity of HCl solution = 0.75 M

Volume of HCl solution = 25.0 mL = 0.025 L

Putting values in equation 1, we get:

\text{Moles of} HCl={0.75}\times{0.025}=0.01875moles  

CaCO_3(s)+2HCl(aq)\rightarrow CaCl_2(s)+CO_2(g)+H_2O(l)  

According to stoichiometry :

2 moles of HCl require = 1 mole of CaCO_3

Thus 0.01875 moles of HCl will require=\frac{1}{2}\times 0.01875=0.009375moles  of CaCO_3

Mass of CaCO_3=moles\times {\text {Molar mass}}=0.009375moles\times 100g/mol=0.9375g

Thus 0.9375 g of CaCO_3 is required to react with 25.0 ml of 0.75 M HCl

6 0
3 years ago
Which model of the atom was used as a result of JJ Thomson's cathode ray
mariarad [96]

Answer:

a. Plum pudding model

Explanation:

The plum pudding model of the atom was proposed by J.J. Thomson. It was the model he derived from his experiment on the gas discharge tube.

J.J Thomson was the first person to discover electrons which he called cathode rays because in the discharge tube, they emanate from the cathode.

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MatroZZZ [7]
Concentration=mass/volume.

This should help.
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