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anygoal [31]
3 years ago
8

The mass of solute per 100 mL of solution is abbreviated as (m/v). Mass is not technically the same thing as weight, but the abb

reviation (w/v) is also common. How many grams of sucrose are needed to make 725 mL of a 35.0% (w/v) sucrose solution?
Chemistry
1 answer:
Nimfa-mama [501]3 years ago
3 0

Answer:

\boxed{\text{254 g}}

Explanation:

\begin{array}{rcl}\text{\% m/V} & = & \dfrac{\text{Mass of sucrose}}{\text{Volume of solution}}\\\\\text{Let m}& = &\text{mass of sucrose}\\\dfrac{\text{35.0 g}}{\text{100 mL}}& = & \dfrac{m}{\text{725 mL}}\\\\m & = &\dfrac{\text{35.0 g}\times 725}{100}\\\\ & = &\textbf{254 g}\\\end{array}\\\text{You need $\boxed{\textbf{254 g}}$ of sucrose}

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You measure salt water in a tank to have a density of 1.02 g/mL. A balloon weighs 2.0 g and you weights have a mass of 30.0 g ea
Elden [556K]

Weight of the balloon = 2.0 g

Six weights each of mass 30.0 g is added to the balloon.

Total mass of the balloon = 2.0 g + 6*30.0 g = 182 g

Density of salt water = 1.02 g/mL

Calculating the volume from mass and density:

182g*\frac{mL}{1.02g} =178mL

Converting the volume from mL to cubic cm:

178 mL * \frac{1cm^{3} }{1mL} =178cm^{3}

Assuming the balloon to be a sphere,

Volume of the sphere = \frac{4}{3}πr^{3}

178 cm^{3} = \frac{4}{3}(\frac{22}{7})r^{3}

r = 3.49 cm

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4 0
3 years ago
HELP ASAP PLEASE WHAT IS THIS ANSWER
JulijaS [17]

Answer:

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Explanation:

6 0
3 years ago
Read 2 more answers
A 1.450 g sample of an unknown organic compound , X, is dissolved in 15.0 g of toluene
muminat

Answer:

Molecular weight of the compound = 372.13 g/mol

Explanation:

Depression in freezing point is related with molality of the solution as:

\Delta T_f = K_f \times m

Where,

\Delta T_f = Depression in freezing point

K_f = Molal depression constant

m = Molality

\Delta T_f = K_f \times m

1.33 = 5.12 \times m

m = 0.26

Molality = \frac{Moles\ of\ solute}{Mass\ of\ solvent\ in\ kg}

Mass of solvent (toluene) = 15.0 g = 0.015 kg

0.26 = \frac{Mole\ of\ compound}{0.015}

Moles of compound = 0.015 × 0.26 = 0.00389 mol

Mol = \frac{Mass\ in\ g}{Molecular\ weight}

Mass of the compound = 1.450 g

Molecular\ weight = \frac{Mass\ in\ g}{Moles}

Molecular weight = \frac{1.450}{0.00389} = 372.13\ g/mol

4 0
3 years ago
How did mendel use his training in mathematics to aid his experiments in life science?
Fittoniya [83]
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3 0
3 years ago
What is the Golden Rule of Solubility? A. polar dissolves nonpolar. B. nonpolar dissolves polar. C. like dissolves unlike D. lik
DerKrebs [107]

Answer: D. like dissolves like

Explanation:

The solubility of substances is governed by: Like dissolves like, which states that polar compounds are soluble in polar solvents and non polar compounds are soluble in non polar solvents.

Hydrocarbons are non polar in nature due to less difference between the electronegativities of carbon and hydrogen and thus are soluble in non polar solvents only.

Ionic compounds which are formed by elements with high electronegativity difference are polar in nature and thus dissolve in polar solvents.

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4 0
3 years ago
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