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anygoal [31]
3 years ago
8

The mass of solute per 100 mL of solution is abbreviated as (m/v). Mass is not technically the same thing as weight, but the abb

reviation (w/v) is also common. How many grams of sucrose are needed to make 725 mL of a 35.0% (w/v) sucrose solution?
Chemistry
1 answer:
Nimfa-mama [501]3 years ago
3 0

Answer:

\boxed{\text{254 g}}

Explanation:

\begin{array}{rcl}\text{\% m/V} & = & \dfrac{\text{Mass of sucrose}}{\text{Volume of solution}}\\\\\text{Let m}& = &\text{mass of sucrose}\\\dfrac{\text{35.0 g}}{\text{100 mL}}& = & \dfrac{m}{\text{725 mL}}\\\\m & = &\dfrac{\text{35.0 g}\times 725}{100}\\\\ & = &\textbf{254 g}\\\end{array}\\\text{You need $\boxed{\textbf{254 g}}$ of sucrose}

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How much fluorine (in grams) did the second sample produce? ?Upon decomposition, one sample of magnesium fluoride produced 1.66
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\boxed{\text{2.02 g F}}

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3 years ago
How many molecules of O2 are present in a 3.90L flask at a temperature of 273K and a pressure of 1.00 atm
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 the molecules  of O2 that are  present in 3.90 L  flask   at  a temperature  of 273 K and a pressure of 1.00 atm is 1.047 x 10^23 molecules  of O2



 calculation

Step  1:  used the ideal gas equation to calculate the moles of O2

that is Pv=n RT  where;

P(pressure)= 1.00 atm

V(volume) =3.90 L

n(number of moles)=?

R(gas constant) = 0.0821 L.atm/mol.K

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by  making n the subject of the formula by  dividing  both side by RT

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Step 2: use the Avogadro's  law  constant  to calculate  the number of molecules

that  is  according to Avogadro's law

                           1  mole =  6.02 x10^23  molecules

                             0.174 moles=? molecules

by  cross  multiplication

the number of  molecules

= (0.174  moles x  6.02 x10^23  molecules)/ 1 mole  =1.047 x 10^23 molecules of O2


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