Weight of the balloon = 2.0 g
Six weights each of mass 30.0 g is added to the balloon.
Total mass of the balloon = 2.0 g + 6*30.0 g = 182 g
Density of salt water = 1.02 g/mL
Calculating the volume from mass and density:

Converting the volume from mL to cubic cm:

Assuming the balloon to be a sphere,
Volume of the sphere =
π

r = 3.49 cm
Radius of the balloon = 3.49 cm
Diameter of the balloon = 2 r = 2*3.49 cm = 6.98cm
Answer:
Molecular weight of the compound = 372.13 g/mol
Explanation:
Depression in freezing point is related with molality of the solution as:

Where,
= Depression in freezing point
= Molal depression constant
m = Molality


m = 0.26
Molality = 
Mass of solvent (toluene) = 15.0 g = 0.015 kg

Moles of compound = 0.015 × 0.26 = 0.00389 mol

Mass of the compound = 1.450 g

Molecular weight = 
Mendel use his training in mathematics to aid his experiments in life science by using it for the offspring sexual reproduction. <span>He mainly studied pea plants because they had distinguished characteristics and they were quick to grow. Mendel would create </span>hybrids<span> from the plants. </span>
Answer: D. like dissolves like
Explanation:
The solubility of substances is governed by: Like dissolves like, which states that polar compounds are soluble in polar solvents and non polar compounds are soluble in non polar solvents.
Hydrocarbons are non polar in nature due to less difference between the electronegativities of carbon and hydrogen and thus are soluble in non polar solvents only.
Ionic compounds which are formed by elements with high electronegativity difference are polar in nature and thus dissolve in polar solvents.
Example:
in water.