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3 years ago

11

The net charge on a sulfide ion (s2-) is -2. explain how this ion obtains its charge

1 answer:

Anestetic [448]3 years ago

6 0

Sulfur is a group six element in period 3 with atomic number 16 and an electronic configuration of 2:8:6. Therefore, to attain a stable configuration it requires to gain two electrons forming an ion with a charge of -2. The negative charge is due to the gaining of electrons.

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Metamorphic rocks that melt in a holt fluid can recystallize into a different form of rock

kotykmax [81]

I think that type of rock is call Igneous rock because the igneous rock is molten rock from volcanoes.

7 0

3 years ago

NEED ASAP WILL MARK BRAINLIEST ON TIMER

vladimir1956 [14]

Answer:

The answer is 2.660 mol/l

Explanation:

Given: n= 0.0665, v= 25.00ml

Required: C

C (molarity)= n (of solute)/ v (of solvent) [ standard unit: mol/l]

First convert volume of solvent in its standard unit, i.e. litres(L)

v= 25.00ml/1000= 0.02500L

C = 0.0665 mol / 0.02500 L= 2.660 mL (In proper significant digits i.e. 4 sigdigs)

Therefore, The molarity of the sulfuric acid is 2.660 mol/L :)

3 0

3 years ago

Which statements regarding the Henderson-Hasselbalch equation are true? If the pH of the solution is known as is the pKa for the

Sonbull [250]

Answer:

1, 2, and 3 are true.

Explanation:

The Henderson-Hasselbalch equation is:

pH = pka + log₁₀ $\frac{[A^-]}{[HA]}$

If the pH of the solution is known as is the pKa for the acid, the ratio of conjugate base to acid can be determined. <em>TRUE</em>

pH = pka + log₁₀ $\frac{[A^-]}{[HA]}$

If you know pH and pka:

10^(pH-pka) = $\frac{[A^-]}{[HA]}$

The ratio will be: 10^(pH-pka)

At pH = pKa for an acid, [conjugate base] = [acid] in solution. <em>TRUE</em>

pH = pka + log₁₀ $\frac{[A^-]}{[HA]}$

0 = log₁₀ $\frac{[A^-]}{[HA]}$

10^0 = $\frac{[A^-]}{[HA]}$

1 = $\frac{[A^-]}{[HA]}$

As ratio is 1, [conjugate base] = [acid] in solution.

At pH >> pKa for an acid, the acid will be mostly ionized. <em>TRUE</em>

pH = pka + log₁₀ $\frac{[A^-]}{[HA]}$

If pH >> pKa, 10^(pH-pka) will be >> 1, that means that you have more [A⁻] than [HA]

At pH << pKa for an acid, the acid will be mostly ionized. <em>FALSE</em>

pH = pka + log₁₀ $\frac{[A^-]}{[HA]}$

If pH << pKa, 10^(pH-pka) will be << 1, that means that you have more [HA] than [A⁻]

I hope it helps!

6 0

3 years ago

Define in your own words: Solute, Solvent and Solution.

anyanavicka [17]

The substance that is being dissolved is called the solute and the substance that does the dissolving is called the solvent. So the solvent dissolves in the solute the forming a solution.

6 0

3 years ago

A student uses a magnet to move a 0.0 25 KG metal ball the magnet exerts a force of five in which causes the body to begin movin

givi [52]

Answer:

The acceleration of the ball when it begins to move is 200 m/s²

Explanation:

The given parameters are;

The mass of the metal ball, m = 0.025 kg

The force exerted by the magnet on the ball, F = 5 N

From Newton's second law, F = m × a

Where;

a = The acceleration of the ball

Therefore, by substitution, we have;

5 = 0.025 × a

a = 5/0.025 = 200 m/s²

The acceleration of the ball when it begins to move = 200 m/s²

7 0

3 years ago