What action should be performed when heating a solid to dryness to prevent spattering caused by bumping
1 answer:
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Answer: The molar enthalpy change is 73.04 kJ/mol
Explanation:
moles of HCl=
As NaOH is in excess 0.0415 moles of HCl reacts with 0.0415 moles of NaOH.
volume of water = 100.0 ml + 50.0 ml = 150.0 ml
density of water = 1.0 g/ml
mass of water =
q = heat released
m = mass = 150.0 g
c = specific heat =
= change in temperature =
Thus 0.0415 mol of HCl produces heat = 3031.3 J
1 mol of HCL produces heat =
Thus molar enthalpy change is 73.04 kJ/mol