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Pavlova-9 [17]
3 years ago
14

Suppose that the probability a seed will germinate is 85%. What is the probability that 7 of these seeds will germinate when 10

are planted?
a.0.1298
b.0.385
c.0.12
d.0.141
Mathematics
2 answers:
Viktor [21]3 years ago
6 0
Total number of outcomes of 7 from 10 = 10*9*8 / 3*2*1  = 120
probability of each outcoe is 0.85^7* (0.15)^(3)  = 0.0010819

Required probability = 120 * 0.0010819 =  0.1298
Nuetrik [128]3 years ago
3 0

Answer:A

Step-by-step explanation:

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The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers
stealth61 [152]

Answer:

(a) $62.16

(b) Male: $15.00

Female: $10.06

(c) Confidence Interval for male expenditure is ($106.40, $136.40)

Confidence interval for female expenditure is ($49.18, $69.30)

Step-by-step explanation:

(a) Male expenditure

Sample mean = $135.67, sd=$35, n=40, Z=2.576

Population mean = sample mean - (Z×sd)/√n = 135.67 - (2.576×35)/√40 = 135.67 - 14.27 = $121.40

Female expenditure

Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

$121.40 - $59.24 = $62.16

(b) Male: Error margin = (t-value × sd)/√n

Degree of freedom = n-1 = 40-1= 39. t-value corresponding to 39 degrees of freedom and 99% confidence level is 2.708

Error margin = (2.708×35)/√40 = 94.78/6.32 = $15.00

Female

Degrees of freedom = n-1 = 30-1 = 29. t-value is 2.756

Error margin = (2.756×20)/√30 = 55.12/5.48 = $10.06

(c) Male

Confidence Interval (CI) = (mean + or - error margin)

CI = 121.4 + 15.00 = $136.40

CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

Female

CI = 59.24 + 10.06 = $69.30

CI = 59.24 - 10.06 = $49.18

Confidence Interval is ($49.18, $69.30)

7 0
3 years ago
Which of the following expressions is equivalent to –6?
Inessa [10]

Answer:

the correct answer po is letter A

Step-by-step explanation:

Tinatamad akong mag explain pero tama po 'yan

8 0
2 years ago
Twelve percent of the population is left handed. Approximate the probability that there are at least 20 left-handers in a school
DochEvi [55]

Answer:

Step-by-step explanation:

We would assume a binomial distribution for the handedness of the population. Let x be a random variable representing the type of handedness in the population. The probability of success, p is that a randomly chosen person is left handed only. Then probability of failure is that a chosen person is not left handed only(right handed only or both).

p = 12/100 = 0.12

number of success, x = 20

n = 200

the probability that there are at least 20 left-handers is expressed as P(x ≥ 20)

From the binomial probability calculator,

P(x ≥ 20) = 0.84

8 0
3 years ago
Write a real world situation that could be represented by the equation shown below y= -10x - 15
stich3 [128]
Example (not a very likely example, however):

At 11 pm the temperature is -15 degrees F, and it continues to drop by 10 degrees F every hour.
3 0
3 years ago
Can you use mechanical pencils on the PSAT?
TEA [102]

Answer:

no

Step-by-step explanation:

only number 2 pencils im pretty sure

7 0
2 years ago
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