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sergiy2304 [10]
3 years ago
15

Indentify the 3 types of heat tranfer

Physics
2 answers:
Elenna [48]3 years ago
8 0

Answer:

Heat is transfered via solid material (conduction), liquids and gases (convection), and electromagnetical waves (radiation).

Feel free to ask...follow me

Vlad [161]3 years ago
8 0

Answer:Conduction, Convection and Radiation

Explanation: Conduction heat transfer for solids. Convection is the transfer of heat through fluids. And radiation is the method of heat transfer that does not require any medium for heat to transfer.

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What is entropy and how is it related to string theory?
balu736 [363]

Answer:

Explanation:

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3 years ago
A car traveling with constant speed travels 150 km in 7200s what is the speed of the car
Oksana_A [137]
Velocity is distance/time 

so 150/7200=.0208km/s 

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3 years ago
A top-fuel dragster accelerates from rest to a velocity of 100 m/s in 8 s. What is the acceleration?
seropon [69]

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4 0
3 years ago
An 85,000 kg stunt plane performs a loop-the-loop, flying in a 260-m-diameter vertical circle. at the point where the plane is f
konstantin123 [22]
A) When the plane is flying straight down, there are three forces acting on it:
- the centripetal force  F=m \frac{v^2}{r}, directed toward the center of the circle (so, horizontally)
- the weight of the plane: W=mg, downward, so vertically
- a third force, given by the propulsion of the plane, which is accelerating it towards the ground (because the problem says that the plane has an acceleration of a=12 m/s^2 towards the ground)

The radius of the circle is r= \frac{260 m}{2} = 130 m, so the centripetal force acting on the plane is
F_c=m \frac{v^2}{r} = \frac{(85000 kg)(55 m/s)^2}{130 m}=1.98 \cdot 10^6 N
On the vertical axis, we have two forces: the weight
W=mg=(85000 kg)(9.81 m/s^2)=8.34 \cdot 10^5 N
and the other force F given by the propulsion. Since we know that their sum should generate an acceleration equal to a=12 m/s^2, we can find the magnitude of this other force F by using Newton's second law:
F+mg=ma
F=m(a-g)=(85000kg)(12 m/s^2-9.81 m/s^2)=1.86 \cdot 10^5 N

So, the net force acting on the plane will be the resultant of the centripetal force (acting in the horizontal direction) and the two forces W and F (acting in the vertical direction):
R= \sqrt{(F_c^2+(W+F)^2}=
= \sqrt{(1.98\cdot 10^6N)^2+(8.34 \cdot 10^5N+1.86 \cdot 10^5 N)^2}  =2.23 \cdot 10^6 N

(b) The tangent of the angle with respect to the horizontal is the ratio between the sum of the forces in the vertical direction (taken with negative sign, since they are directed downward) and the forces acting in the horizontal direction, so:
\tan \theta =  \frac{-(W+F)}{F_c}= -0.5
And so, the angle is
\theta = \arctan (-0.5)=-26.8 ^{\circ}
 
7 0
3 years ago
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