Answer:
a. 0.026 M
Explanation:
Molarity is a measure of the molar concentration of a solution. It can be calculated by using the following formula:
Molarity = n/V
Where;
n = number of moles (mol)
V = Volume of solution (L)
Based on the information provided;
V = 23.2mL = 23.2/1000 = 0.0232 L
n = ?
To get the number of moles of KHP, we use the formula:
mole = mass/molar mass
mole (n) = 0.123/204.2
mole (n) = 0.0006024mol
Molarity = n/V
Molarity = 0.0006024 ÷ 0.0232
Molarity = 6.024 × 10^-4 ÷ 2.32 × 10^-2
Molarity = 6.024/2.32 × 10^(-4--2)
Molarity = 2.59 × 10^-2
Molarity = 0.026 M
Answer:
-k slope
The term No is the y intercept(does not mean NO) y-intercept
Explanation:
For a straight line graph, the normal equation could be written as
y = mx + c
Where m is the slope and c is the y intercept.
Writing the equation is the form of y = mx + c gives the following;
lnN = -kt + No
As obtained from the question, t is plotted in the x-axis, while lnN is the plot on the y-axis.
Now, we are asked to obtain the slope and the y-intercept. It can be seen that the slope is the coefficient of the term x in this case t. Hence, our slope is -k.
The y-intercept is the other term which in this case is No
The gross colors can be imparted to the flame by the metal ion solutions .
1.To serve as an excitation source, turn on a Bunsen burner.
2. Perform flame tests on the chloride solutions of Li+, Na+, K+, Ca2+, Sr2+, and Ba2+ as instructed by your lab instructor. Wearing the unique glass blower glasses, take note of the obscene hue that each ion contributes to the flame. With one exception: in order to view the sodium flame, you must remove the special glasses that suppress sodium emissions.
3. Obtain two unidentified answers and note their numerical values. Using the ugly hue the solution gives the flame as a guide, identify the metal ions that are present.
One of the six ions you tested will make up the particle.
To know more about continuous spectrum, please refer:
brainly.com/question/28032005
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Kepler’s third law exhibits the relationships between the distance of a planet from the sun and the period of its revolution. Kepler’s third law is also sometimes referred to as the law of harmonies.
Kepler’s third law compares the orbital period and the radius of an orbit of a planet to the distance of the planet to the sun. It states mathematically that the more distant a planet is from the sun the greater its orbital period will be. The period of revolution of a planet is measured in days, weeks, months or years. For example, Earth’s period of revolution is 365 days.
