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8_murik_8 [283]
2 years ago
13

The pOH of a solution is 6.0. Which statement is correct? Use p O H equals negative logarithm StartBracket upper O upper H super

script minus EndBracket. and p H plus P O H equals 14.. The pH of the solution is 20.0. The concentration of OH– ions is 1.0 times 10 to the negative 8 moles per liter.. The concentration of OH– ions is 1.0 times 10 to the 6 moles per liter.. The pH of the solution is 8.0.
Chemistry
2 answers:
castortr0y [4]2 years ago
6 0

Answer:

The pH of the solution is 8.0.

Explanation:

taking the test rn

Natali5045456 [20]2 years ago
4 0

Answer: D.The pH of the solution is 8.0.

Explanation: taking the test!

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Given that a for HBrO is 2. 8×10^−9 at 25°C. What is the value of b for BrO− at 25°C?
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If Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

<h3>What is base dissociation constant? </h3>

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

HCN --- (H+) + (CN-)

Given,

The value of Ka for HCN is 2.8× 10^(-9)

The correlation between base dissociation constant and acid dissociation constant is

Kw = Ka × Kb

Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{2.8×10^(-9) }

= 3.5× 10^(-6)

Thus, we find that if Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

DISCLAIMER: The above question have mistake. The correct question is given as

Question:

Given that Ka for HBrO is 2. 8×10^−9 at 25°C. What is the value of Kb for BrO− at 25°C?

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