2C4H10 + 13O2 -> 8CO2 + 10H2O
Answer:
All the statements are correct but "all chemical reactions can be classified as one of the five general types".
Explanation:
Hello,
In this case, I assume you are looking for the wrong statement as long as the following ones are correct and matches with the foundations of chemical reactions:
- The only way to determine the products of a reaction is to carry out the reaction. This is clear, because after the chemical reaction is done, one identifies the products.
- Complete combustion has occurred when all the carbon in the product is in the form of carbon dioxide. This is clear due to a 100% conversion.
- A single reactant is the identifying characteristic of a decomposition reaction. All decomposition reactions have only one reactant which breaks into less complex species.
So the wrong statement is:
- All chemical reactions can be classified as one of five general types. This is wrong because there are four widely known chemical reactions: synthesis, decomposition, simple displacement and double displacement.
Best regards.
Explanation:
The electrical force between two objects is given by the formula as follows :

k is electrostatic constant
q₁ and q₂ are electric charges
d is distance between charges
So, the two force between two charged objects depends on the product of charges and distance between charges.
Answer:
They have the same number of atoms
Explanation:
The mole (symbol: mol) is the base unit of amount of substance.
Think of mole meaning like inch. An inch of grass is the same as an inch of a flower. Mole is the standard measuring unit of atoms.
Following steps are involved in the reaction
Step 1: <span>Cl2(g)⇌2Cl(g)
Step 2: </span><span>Cl(g)+CHCl3(g)→HCl(g)+CCl3(g)
Step 3: </span><span>Cl(g)+CCl3(g)→CCl4(g)
......................................................................................................
Overall reaction : </span>Cl2(g) + CHCl3(g) → HCl(g) + CCl4(g)
Note: Overall reaction is obtained by adding step 1-3 and canceling common terms that are present on reactant and product sides.