Answer:
64.52 mg.
Explanation:
The following data were obtained from the question:
Half life (t½) = 1590 years
Initial amount (N₀) = 100 mg
Time (t) = 1000 years.
Final amount (N) =.?
Next, we shall determine the rate constant (K).
This is illustrated below:
Half life (t½) = 1590 years
Rate/decay constant (K) =?
K = 0.693 / t½
K = 0.693/1590
K = 4.36×10¯⁴ / year.
Finally, we shall determine the amount that will remain after 1000 years as follow:
Half life (t½) = 1590 years
Initial amount (N₀) = 100 mg
Time (t) = 1000 years.
Rate constant = 4.36×10¯⁴ / year.
Final amount (N) =.?
Log (N₀/N) = kt/2.3
Log (100/N) = 4.36×10¯⁴ × 1000/2.3
Log (100/N) = 0.436/2.3
Log (100/N) = 0.1896
Take the antilog
100/N = antilog (0.1896)
100/N = 1.55
Cross multiply
N x 1.55 = 100
Divide both side by 1.55
N = 100/1.55
N = 64.52 mg
Therefore, the amount that remained after 1000 years is 64.52 mg
Neutrons have no electrical charge.
+2, because the element has more protons than electrons now
233.1g
Explanation:
Given:
Formula units of FeCl₃ = 8.65 x 10²³ formula units
Unknown:
Mass of the FeCl₃ = ?
Solution:
The formula unit is the same as the amount of subatomic particles in an atom.
1 mole of a substance = 6.02 x 10²³ formula units
For 8.65 x 10²³ formula units; the number of moles;
Number of moles = = 1.44moles
Now to find the mass of FeCl₃;
Mass of FeCl₃ = 1.44 x 162.2 = 233.1g
learn more:
Number of moles brainly.com/question/1841136
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