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Advocard [28]
3 years ago
12

Identify the vertical asymptotes of f(x) = 2 over quantity x squared plus 3 x minus 10.

Mathematics
1 answer:
zysi [14]3 years ago
3 0
The function is:
f ( x ) = 2 / ( x² + 3 x - 10 )
x² + 3 x - 10 = x² + 5 x - 2 x - 10 = x ( x + 5 ) - 2 ( x + 5 ) =
= ( x + 5 ) ( x - 2 )
x + 5 = 0 => x = - 5
x - 2 = 0 => x = 2
Answer:
The vertical asymptotes are: x = - 5 and x = 2.
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Pls solve the simultaneous equation in the attachment.
siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

\frac{x}{2}-\frac{y}{5}=1 ----> equation A

y-\frac{x}{3}=8 ----> equation B

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5x-2y=10 ----> equation C

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15x-2x-48=30

15x-2x=48+30

Combine like terms

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y=\frac{6}{3}+8

y=10

The solution is the ordered pair (6,10)

Part b) we have

xy=21 ---> equation A

x+5y=22 ----> equation B

isolate the variable x in the equation B

x=22-5y ----> equation C

substitute equation C in equation A

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22y-5y^2=21

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Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

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x=22-5(3)=7

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

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4 years ago
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Answer:

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Step-by-step explanation:

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Add it all up and it equals 52 sides in total

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