333,000 Joules is the amount of energy (heat) in joules required to raise the temperature of 5 kg of iron from 50°C to 200°C.
Explanation:
Data given:
mass of iron 5 Kg or 5000
initial temperature = 50 degree centigrade
final temperature = 200 degrees centigrade
change in temperature (Δ T= 200 -50 degrees centigrade)
= 150 °C
cp (specific heat capacity of iron) = 0.444j/gram C
q (heat supplied) = ?
applying the formula,
q=mcΔT
putting the values in the equation:
q = 5000 X 0.444 X150
q = 333,000 Joules of energy.
The heat required 333,000 Joules of energy is required.
Answer:
B) we will convert the 10 g of NaCl into moles.
Explanation:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
we will convert the 10 g of NaCl into moles.
Number of moles of NaCl:
Number of moles = mass/molar mass
Number of moles = 10 g/ 58.44 gmol
Number of moles = 0.17 mol
1 Kg = 1 L
Molarity = 0.17 mol / 2 L
Molarity = 0.085 mol/L
Molarity = 0.085 M
Answer:
The answer to your question is 432 g of CO₂
Explanation:
Data
CaCO₃ = 983 g
CaO = 551 g
CO₂ = ?
Balanced reaction
CaCO₃ (s) ⇒ CaO (s) + CO₂ (g)
This reaction is balanced, to solve this problem just remember the Lavoisier Law of conservation of mass that states that the mass of the reactants is equal to the mass of the products.
Mass of reactants = Mass of products
Mass of CaCO₃ = Mass of CaO + Mass of CO₂
Solve for CO₂
Mass of CO₂ = Mass of CaCO₃ - Mass of CaO
Mass of CO₂ = 983 g - 551 g
Simplification
Mass of CO₂ = 432 g
Answer:
Overall reaction equation;
2NO(g) +Cl2(g) -----> 2NOCl (g)
Explanation:
Given
1) NO(g) + Cl2(g) → NOCl2(g)
2) NOCl2(g) + NO(g) → 2NOCl(g)
Overall reaction equation;
2NO(g) +Cl2(g) -----> 2NOCl (g)
k1= [NOCl2]
k-1= [NO] [Cl2]
k2 = [NOCl2] [NO]
Equilibrium for the first equation (reaction 1)
K= k1/k-1 = [NOCl2]/[NO] [Cl2]
Therefore
[NOCl2] = k1/k-1 [NO] [Cl2]
Rate= k2× k1/k-1 [NO]^2 [Cl2]
Rate = Koverall [NO]^2 [Cl2]
Where Koverall= k1k2/k-1
Answer:
The answer is "Upland sandpipers are primary and secondary consumers because they eat grasses and grasshoppers".
Explanation:
The limited farmland nutrition web, that reveals better which Upland sandpipers were main and secondary customers in this farmland since they eat grass with grasshoppers.
- It also eat butterflies, bricks, shrimps, mollusks, worms, and nematodes, throughout contrast to bugs, which sandpipe gathers seed of hay, plants, conifers, and rice, rye, or strawberries.
- Highlands dragonflies sometimes assemble in recently burnt fields with such a wealth of squirrels.
