The given questions belongs to the concept of limiting reagent.
The number of moles of carbon dioxide produced when 4.6 moles of dioxygen reacts is 4.6 moles.
<h3 /><h3>What is Limiting Reagent ?</h3>
The limiting reagent (or limiting reactant or limiting agent) in a chemical reaction is a reactant that is totally consumed when the chemical reaction is completed.
Given ;
Moles of Oxygen = 4.6
To find;
Moles of Carbon di oxide = ?
The reaction that forms 
is as follows:
C(s) + 
(g) --> (g)
This means that is consumed and is produced in a 1:1 ratio.
If we consume 4.6 mol , then we produce 4.6 mol .
Hence, 4.6 mol are produced when 4.6 mol of oxygen reacts.
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Hey there!
RbOH
Rb: 1 x 85.468 = 85.468
O: 1 x 16 = 16
H: 1 x 1.008 = 1.008
------------------------------------
102.476
The molar mass of RbOH is 102.476 g/mol.
Hope this helps!
Answer:
Half life of phosphorous-32 = 14 days
Explanation:
Given data:
Total mass of phosphorous-32 = 2.0 g
After 42 days mass left = 0.25 g
Half life of phosphorous-32 = ?
Solution:
First of all we will calculate the number of half lives passed.
At time zero = 2.0 g
At first half life = 2.0 g/2 = 1.0 g
At 2nd half life = 1.0 g/2 = 0.5 g
At 3rd half life = 0.5 g/2 = 0.25 g
Half life:
Half life = T elapsed / half lives
Half life = 42 days/ 3
Half life = 14 days
The force of an object due mass and gravity.it can also be defined as the force exerted by gravity on a body
