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slega [8]
3 years ago
5

How do particles in a sample of matter interact when the sample is in a different state (solid,

Chemistry
1 answer:
alisha [4.7K]3 years ago
6 0
Particles in a: gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.
I hope this helps
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Calculate the number of formula units in 2.50 mol NaNO
marta [7]

The number of formula units in 2.50 mol of the compound is  15.1 * 10^23.

The question is unclear whether NaNO2 or NaNO3 is implied. However,in either case, the solution applies equally.

6.02 * 10^23 formula units of the compound are contained in 1 mole

x formula units are contained in 2.5 moles of the compound

x = 6.02 * 10^23 formula units * 2.5 moles/ 1 mole

x = 15.1 * 10^23 formula units of the compound.

Learn more; brainly.com/question/9743981

3 0
2 years ago
The number 0.00003007 expressed in exponential notation is
antiseptic1488 [7]
The exponential is 3.007 times 10 to the -5
5 0
3 years ago
A green powder was placed into a beaker of water. After it was stirred the water looked cloudy and lumps of powder could still b
sukhopar [10]

Answer:

it make poisionus police come and took away

7 0
2 years ago
Which of the following molecules would you expect to have a dipole moment of zero?
Mashcka [7]

Answer:

CCl2=CCl2

Explanation:

Recall that the individual dipole moments in a symmetrical molecule cancel out each other thereby making the overall molecule to be non polar.

CCl2=CCl2 contain individual polar bonds but the molecule is highly symmetrical thus its dipole cancel out and the molecule has no overall dipole moment, hence CCl2=CCl2 has a dipole moment of zero .

6 0
3 years ago
In a 71.4 g sample of nahco 3 3 ​ , how many grams of sodium are present?
sweet [91]

There are 19.5 g Na in 71.4 g NaHCO₃

Calculate the <em>molecular mass of NaHCO₃</em>.

1 Na = 1 × 22.99 u = 22.99   u

1 H   = 1 × 1.008 u =    1.008 u

1 C   = 1 × 12.01  u =  12.01    u

3 O = 3 × 16.00 u =  <u>48.00  u </u>

               TOTAL =  84.008 u

So, there are 22.99 g of Na in 84.008 g NaHCO₃.

∴ Mass of Na = 71.4 g NaHCO₃ × (22.99 g Na/84.008 g NaHCO₃) = 19.5 g Na

4 0
3 years ago
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