There are 2 answers for this in my opinion
1. nothing happens because its still in the origin and that won't change
2. depending on which way you turn it the points will change based on that

so if you know how to use a graph you should be good

7 0

3 years ago

(2x+2y=10)+(-x+y=1)

ruslelena [56]

$\bf \begin{cases}
2x+2y=10\\
-x+y=1
\end{cases}\\\\
-------------------------------\\\\
-x+y=1\implies y=1+x\impliedby \textit{let's plug that in the first equation}
\\\\\\
2x+2(\stackrel{y}{1+x})=10\implies 2x+2+2x=10\implies 4x=8
\\\\\\
x=\cfrac{8}{4}\implies \boxed{x=2}\impliedby \textit{let's plug that in the second one}
\\\\\\
-(\stackrel{x}{2})+y=1\implies \boxed{y=3}$

7 0

3 years ago

Find K by evaluating Limit

Lubov Fominskaja [6]

Answer:

Step-by-step explanation:

$\lim_{x \to \infty}\frac{1-cos4x}{1-cos2x}= \lim_{x \to 0} \frac{(1-cos4x)'}{(1-cos2x)'}= \lim_{x \to 0}\frac{4sin4x}{2sin2x}= \lim_{x \to 0}\frac{2*2sin2xcos2x}{sin2x}\\ = \lim_{x \to 0}4cos2x\\ =4$

{L'Hospital's rule}

<em>I hope this helps you</em>

6 0

2 years ago