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4 years ago

One city is at a higher latitude than another city. How does this make the two climates different?

Chemistry

1 answer:

Alex73 [517]4 years ago

4 0

Answer:

The higher latitude may have a colder climate than the lower latitude

Explanation:

For example, the higher the latitude of a given place (the farther away it is from the equator), the sharper the angle of the sun's rays that reach it, meaning that the rays of the sun are spread across a broader area. Therefore, higher latitudes receive less heat than lower latitude areas nearer the equator.

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a gas that exerts a pressure of 215 torr in a container with a volume of 51.0 mL will exert a pressure of ? torr when transferre

zhannawk [14.2K]

To calculate the new pressure, we can use Boyle’s law to relate these two scenarios (Boyle’s law is used because the temperature is assumed to remain constant). Boyle’s law is:

P1V1 = P2V2,

Where “P” is pressure and “V” is volume. The pressure and volume of the first scenario is 215 torr and 51 mL, respectively, and the second scenario has a volume of 18.5 L (18,500 mL) and the unknown pressure - let’s call that “x”. Plugging these into the equation:

(215 torr)(51 mL) =(“x” torr)(18,500 mL)
x = 0.593 torr

The final pressure exerted by the gas would be 0.593 torr.

Hope this helps!

3 0

4 years ago

Please help also some of them may be multiple choice, thank you.

Maurinko [17]

Answer: what are the answers to the questions

Explanation:

5 0

3 years ago

On combustion, 1.0 L of a gaseous compound of hydrogen, carbon, and sulfur gives 2.0 L of CO2, 3.0 L of H2O vapor, and 1.0 L of

Murrr4er [49]

Answer:

The empirical formula of the organic compound is = $C_2H_6S_1$

Explanation:

At STP, 1 mole of gas occupies 22.4 L of volume.

Moles of $CO_2$ gas at STP occupying 2.0 L = n

$n\times 22.4L=2.0L$

$n=\frac{2.0 L}{22.4 L}=0.08929 mol$

Moles of carbon in 0.08920 mol = 1 × 0.08920 mol = 0.08920 mol

Moles of $H_2O$ gas at STP occupying 3.0 L = n'

$n'\times 22.4L=3.0L$

$n'=\frac{3.0 L}{22.4 L}=0.1339 mol$

Moles of hydrogen in 0.1339 moles of water vapor = 2 × 0.1339 mol = 0.2678 mol

Moles of $SO_2$ gas at STP occupying 1.0 L = n''

$n''\times 22.4L=1.0L$

$n''=\frac{1.0 L}{22.4 L}=0.04464 mol$

Moles of sulfur in 0.04464 mol = 1 × 0.04464 mol = 0.04464 mol

Moles of carbon , hydrogen and sulfur constituent of that organic compound .

Moles of carbon in 0.08920 mol = 1 × 0.08920 mol = 0.08920 mol

Moles of hydrogen in 0.1339 moles of water vapor = 2 × 0.1339 mol = 0.2678 mol

Moles of sulfur in 0.04464 mol = 1 × 0.04464 mol = 0.04464 mol

For empirical; formula divide the least number of moles from all the moles of elements.

carbon = $\frac{0.08920 mol}{0.04464 mol}=2$

Hydrogen = $\frac{0.2678 mol}{0.04464 mol}=6$

Sulfur = $\frac{0.04464 mol}{0.04464 mol}=1$

The empirical formula of the organic compound is = $C_2H_6S_1$

3 0

3 years ago

Chlorophyll is essential to photosynthesis because it traps the _______________ needed.

AveGali [126]

Your answer is D.

Chlorophyll traps in the sunlight needed for the process known as 'photosynthesis' .

7 0

3 years ago

Read 2 more answers

1.00 mL of a 3.55 × 10–4 M solution of oleic acid is diluted with 9.00 mL of petroleum ether, forming solution A. Then 2.00 mL o

Leto [7]

Answer:

Concentration of solution B is $7.10\times 10^{-6}M$

Explanation:

Solution A: Total volume of solution A = (9.00+1.00) mL = 10.00 mL

According to law of dilution, $C_{1}V_{1}=C_{2}V_{2}$

where $C_{1}$ and $C_{2}$ are initial and final concentration respectively. $V_{1}$ and $V_{2}$ are initial and final volume respectively.

Here $C_{1}$ = $3.55\times 10^{-4}M$ , $V_{1}$ = 1.00 mL, $V_{2}$ = 10.00 mL

So, $C_{2}=\frac{C_{1}V_{1}}{V_{2}}$ = $\frac{3.55\times 10^{-4}M\times 1.00mL}{10.00mL}=3.55\times 10^{-5}M$

So, concentration of solution A = $3.55\times 10^{-5}M$

Solution B: Total volume of solution B = (2.00+8.00) mL = 10.00 mL

Similarly as above, $C_{2}=\frac{C_{1}V_{1}}{V_{2}}$ = $\frac{3.55\times 10^{-5}M\times 2.00mL}{10.00mL}=7.10\times 10^{-6}M$

So, concentration of solution B = $7.10\times 10^{-6}M$

7 0

4 years ago