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dybincka [34]
3 years ago
11

The first stage in designing your presentation is to make a list of questions that will enable you to do research. The list is d

ivided by topic. Your presentation should answer these questions:
Chemical Reactions of Fossil Fuels

What kind of chemical reaction occurs when fossil fuels and biomass are burned? What is produced in addition to energy?
What is acid rain? Which fossil fuel causes acid rain? What are the chemical reactions that produce the acid?
Difference Between Biomass and Fossil Fuels

In terms of environmental impact, what’s the difference between natural gas, coal, and biomass? Consider both carbon dioxide (CO2) emissions and acid rain.
What’s the difference between nonrenewable and renewable energy sources? Is biomass a renewable energy source?
What’s a new discovery that makes it easier to use biomass as an energy source?
Comparing Biomass with Other Renewable Energy Sources

What are the pros and cons of several renewable energy sources? Renewable energy sources include biomass, wind power, hydropower, solar power, and geothermal power.
Making Recommendations for Energy Choices

Which renewable energy sources should be developed in your area, and why? Consider abundance of the energy source, ease of setup in your area, and cost.
Review the seven questions. Write a few sentences summarizing what you already know about these topics.
Chemistry
1 answer:
fredd [130]3 years ago
5 0
Do you want me to answer with a paragraph or just something simple Nanak??
You might be interested in
1.72 mol of LiCl in 37.5 L of solution
givi [52]
<h3>Answer:</h3>

Molarity is 0.046 M

<h3>Explanation:</h3>

We are given;

1.72 mol of LiCl in 37.5 L of solution

We will take the question to be; calculate the molarity of LiCl

Therefore,

we can start by defining molarity as the concentration of a solution in moles per liter.

Molarity of a solution is calculated by dividing the number of moles of solute by the volume of solution.

Molarity = Moles of solute ÷ Volume of the solution

Thus, in this case;

Molarity of LiCl = Moles of LiCl ÷ Volume of the solution

                          = 1.72 moles ÷ 37.5 L

                          = 0.0459 M

                         = 0.046 M

Therefore, the molarity of LiCl solution is 0.046 M

4 0
4 years ago
Can someone help me please
iren [92.7K]

Answer:

Particle energy

Explanation:

5 0
3 years ago
Read 2 more answers
PLEASE HELP ANYONE IM TOO DUMB TO ANSWER THESE :(
AlladinOne [14]

Answer:

The "2" applies only to the sodium, and sugar is a substance

Explanation:

The amount of atoms in an element are written using small letters after the element they refer to.

3 0
4 years ago
Ocean waves observed to travel along the water surface during a developing storm. A coast guard weather station observes that th
yawa3891 [41]

The horizontal distance represents wavelength λ. The time represents the period of the wave T.

Wave speed is given by v= λ/T

Hence, those are the only parameters needed.


Note: the vertical distance is for calculating amplitude which is not used in calculating wave speed.

6 0
4 years ago
1. How many grams are there in 7.5 x 1023 molecules of H2SO4?
Karo-lina-s [1.5K]

Answer:

I cannot give you all the answer but I can help you to solve those.

Explanation:

The first question:

How many grams are there in 7.5×10^{23} molecules of H_{2} SO_{4}?

So we need to find the molecular mass first, use your periodic table,

And then we can find out 2+32+16×4=98 g/mol

Then, we need to find how many moles, by using Avogadro's constant:

Avogadro's constant: 1 mole = 6.02×10^{23}

∴\frac{7.5*10^{23} }{6.02*10^{23}}=1.25 mol(2d.p.)

Lastly, find the grams using the formula M= \frac{m}{n}

m=Mn

m=1.25*98

m=122.5g

-------------------------------------------------------------------------------------------------------------

In conclusion, use those formula to help you:

M= \frac{m}{n} (which M = molecular mass(atomic mass) m=mass of the substance and n = moles)

Avogadro's constant: \frac {molecular mass} {6.02*10^{23}} = moles

5 0
3 years ago
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