2KClO₃ → 2KCl + 3O₂
mole ratio of KClO₃ to O₂ is 2 : 3
∴ if moles of O₂ = 5 mol
then moles of KClO₃ =

= 3.33 mol
Mass of KClO₃ needed = mol of KClO₃ × molar mass of KClO₃
= 3.33 mol × ((39 × 1) + (35.5 × 1) + (16 × 3) g/mol
= 407.93 g
Answer:
Glucose and oxygen are required for cellular respiration. As the law of conversation states, in a biochemical reaction, mass is conserved. The mass of hydrogen in the glucose is therefore conserved in the water molecules products.
500 grams Calcium Nitrate to mol= 3.04715
Answer:
D
Explanation:
THERE ARE 3 HYDROGEN ATOMS AND 1 NITROGEN SUPPORTING THE FORMULA OF AMMONIA NH3 AND TOTAL ATOMS IS ALSO 4.