Answer:
The correct answer is - 66g.
Explanation:
Given:
molecules of CO2 = 9.03 x 10^23
We know:
1 mole of any substance = 6.02x10^23 molecules. (Avogadro's number)
M (CO2) = 12 + (2x16) = 12 + 32 = 44g
Solution:
The mass of CO2 with 9.03x10^23 molecules would be:
44g of CO2 = 6.02x10^23 molecules.
So, the mass in grams of CO2 (X) = 9.03x10^23 molecules
Xg of CO2 = (44x9.03x10^23)/6.02x10^23 = 66g
Thus, the correct answer would be - 66gm.
Answer:
C. They change the substance into another substance.
Explanation:
Hope it helps!!
Answer:
6 days
Explanation:
The following data were obtained from the question:
Original amount (N₀) = 100 mg
Amount remaining (N) = 6. 25 mg
Time (t) = 24 days
Half life (t½) =?
Next, we shall determine the decay constant. This can be obtained as follow:
Original amount (N₀) = 100 mg
Amount remaining (N) = 6. 25 mg
Time (t) = 24 days
Decay constant (K) =?
Log (N₀/N) = kt / 2.303
Log (100/6.25) = k × 24 / 2.303
Log 16 = k × 24 / 2.303
1.2041 = k × 24 / 2.303
Cross multiply
k × 24 = 1.2041 × 2.303
Divide both side by 24
K = (1.2041 × 2.303) / 24
K = 0.1155 /day
Finally, we shall determine the half-life of the isotope as follow:
Decay constant (K) = 0.1155 /day
Half life (t½) =?
t½ = 0.693 / K
t½ = 0.693 / 0.1155
t½ = 6 days
Therefore, the half-life of the isotope is 6 days
Answer:The solution is in the attached file
Explanation:
well according to what i know....headlights only let you see about 350 feet ahead...hope it helps :)
