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sukhopar [10]
2 years ago
9

Suppose a current of 0.880 A flows through a copper wire for 132. seconds. Calculate how many moles of electrons travel through

the wire. Be sure your answer has the correct unit symbol and the correct number of significant digits.
Chemistry
1 answer:
Alika [10]2 years ago
8 0

Answer:

0.00120 moles

Explanation:

Given that:-

Current, I = 0.880 A

Time, t = 132 seconds

Considering:-

I=\frac{Charge,\ q}{t}

0.880\ A=\frac{q}{132\ sec}

Charge=0.880*132 C = 116.16 C

Also, 1 mole of electrons contain a charge of 96500 C

Thus, Moles = \frac{116.16}{96500}=0.00120 moles

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Answer: measure the mass (48.425g) of KCl

Explanation:

To prepare the solution 0.65M KCl we must measure the mass of KCl that would be dissolved in 1L of the solution. This can be achieved by:

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Mass conc of KCl = 0.65 x 74.5 = 48.425g

Therefore, to make 0.65M KCl, we must measure 48.425g

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Part 1. A chemist reacted 12.0 liters of F2 gas with NaCl in the laboratory to form Cl2 gas and NaF. Use the ideal gas law equat
galben [10]

The mass of NaCl needed for the reaction is 91.61 g

We'll begin by calculating the number of mole of F₂ that reacted.

  • Volume (V) = 12 L
  • Temperature (T) = 280 K
  • Pressure (P) = 1.5 atm
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Number of mole (n) =?

PV = nRT

1.5 × 12 = n × 0.0821 × 280

18 = n × 22.988

Divide both side by 22.988

n = 18 / 22.988

n = 0.783 mole

Next, we shall determine the mole of NaCl needed for the reaction.

F₂ + 2NaCl —> Cl₂ + 2NaF

From the balanced equation above,

1 mole of F₂ reacted with 2 moles of NaCl.

Therefore,

0.783 mole F₂ will react with = 0.783 × 2 = 1.566 moles of NaCl.

Finally, we shall determine the mass of 1.566 moles of NaCl.

  • Mole = 1.566 moles
  • Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
  • Mass of NaCl =?

Mass = mole × molar mass

Mass of NaCl = 1.566 × 58.5

Mass of NaCl = 91.61 g

Therefore, the mass of NaCl needed for the reaction is 91.61 g

Learn more about stiochoimetry: brainly.com/question/25830314

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The answer is 1.5*10^-12 square meters. For a detailed calculation, please refer to the attachment.
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