Answer:
18.76atm
Explanation:
Using the formula V1P1/T1 = V2P2/T2, from combined gas law. Volume is constant since we have not been given. Therefore the formula comes to be; P1/T1 = P2/T1
To get P2 = T2(P1/T1)
Where P2 is final pressure
P2 = 239K ( 23atm/293K)
=18.76atm
If Im not wrong i think its rain,snow,hail,and sleet...hope this helps you
One of the many ways in order to solve for the vapor pressure of pure components at a given temperature is through the Antoine's equation which is written below,
P = 10^(A - B/C+T)
where A, B, and C are constants and T is the temperature in °C and P is the vapor pressure in mm Hg.
For hexane,
A = 7.01
B = 1246.33
C = 232.988
Substituting the known values,
P = 10^(7.01 - 1246.33/232.988+25)
<em> P = 151.199 mm Hg</em>
Answer:
no. of water molecules associated to each molecule of
= 4
Explanation:
Mass of
before heating = 19.8 g
Mass of
after heating = 12.6 g
Difference in mass of
before and after heating
= 19.8 - 12.6 = 7.2 g
Difference in mass corresponds to mass of water driven out.
Molar mass of water = 18 g/mol
No. of moles of water = 
Mass of
obtained after heating is mass of anhydrous
.
Mass of anhydrous
= 12.6 g
Molar mass of
= 125.9 g/mol
No. of mol of anhydrous
= 
so,
0.1 mol of
have 0.4 mol of water
1 mol of
will have = 
Hence, no. of water molecules associated to each molecule of
= 4