Hello, here’s the answer to your question. Converting ammonia to nitrate, which is absorbed by plants
The given question is incomplete. The complete question is:
When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.
Answer: The vant hoff factor for sodium chloride in X is 1.9
Explanation:
Depression in freezing point is given by:
= Depression in freezing point
= freezing point constant
i = vant hoff factor = 1 ( for non electrolyte)
m= molality =
Now Depression in freezing point for sodium chloride is given by:
= Depression in freezing point
= freezing point constant
m= molality = 
Thus vant hoff factor for sodium chloride in X is 1.9
Answer:
Situation B indicates the significant depression of temperature in the wet bulb thermometer.
Answer Statement: B
Explanation:
Temperature Depression & Relative Humidity
As we can see that there are four cases to study the affect of relative humidity on the temperature measured by thermometers, set up in different situations i.e., one is dry and the other one is dry.
As situation B describes the most admissible temperature drop in the wet bulb thermometer with a relative humidity of approximately 17% i.e., this can be the appropriate to reflect the lowest relative humidity with a fact that the relative humidity reduces with a larger count of temperature depression. Whereas, the relative humidity for other situations are resulting much higher.
Explanation:
Not only did outermost electron determine the valence electron, but also <em>periodic</em><em> </em><em>table</em><em>.</em><em> </em>whatever group they fall into in periodic table each valence electrons present in a particular atom e.g K and Ca belong to group 1 and 2 respectively and k has 1 and Ca have 2 in each outermost electron
Answer:
See below.
Step-by-step explanation:
The two isotopes are Cl-35 and Cl-37.
The average atomic mass (35.45 u) is closer to 35 u, so most of the atoms are Cl-35.
mass number = number of protons + number of neutrons
A = p + n
35 = 17 + n
n = 35 – 17
n = 18
∴ Most chlorine atoms contain 18 neutrons.
