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8090 [49]
2 years ago
12

What are the 4 forms of precipitation

Chemistry
2 answers:
Sergeu [11.5K]2 years ago
7 0
1. rain
2. snow
3. hail
4. sleet
yKpoI14uk [10]2 years ago
5 0
If Im not wrong i think its rain,snow,hail,and sleet...hope this helps you

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When copper (Cu) and oxygen (O) combine, two different compounds are formed. The first compound contains 88.8% copper by mass, a
marusya05 [52]
1) Chemical reaction 1: 4Cu + O₂ →  2Cu₂O.
n(Cu) = 88,8 ÷ 63,55.
n(Cu) = 1,4.
n(O) = 11,2 ÷ 16.
n(O) = 0,7.
n(Cu) : n(O) = 1,4 : 0,7.
n(Cu) : n(O) = 2 : 1.
Compound is Cu₂O.
2) Chemical reaction 2: 2Cu + O₂ →  2CuO.
n(Cu) = 79,9 ÷ 63,55.
n(Cu) = 1,257.
n(O) = 20,1 ÷ 16.
n(O) = 1,257.
n(Cu) : n(O) = 1,257 : 1,257.
n(Cu) : n(O) = 1 : 1.
Compound is CuO.
6 0
3 years ago
Please help!! A lot of points!!
Artist 52 [7]
Mean: the average. you have to add the values of the numbers and then divide by the amount of numbers there are. a common mistake to avoid is forgetting to divide the numbers at the end or subtracting them instead of adding.

mean: the middle number. you would first need to order the numbers from least to greatest. a common mistake to avoid is finding the middle number before ordering it from least to greatest

these two can also be commonly mistaken for one another because of the similar spelling.
7 0
3 years ago
How many grams of glucose are needed to prepare 400. g of a 2.00% (m/m) glucose solution g?
Dominik [7]
The grams   of glucose  are  needed  to  prepare  400g  of  a 2.00%(m/m)  glucose  solution  g  is  calculated  as  below

=% m/m =mass  of the solute/mass  of  the  solution  x100

let mass of   solute  be represented  by  y
mass  of solution = 400 g
 % (m/m) = 2% = 2/100

 grams  of  glucose  is  therefore =2/100 =  y/400
by cross  multiplication

100y = 800
divide   both side  by  100

y= 8.0 grams



5 0
3 years ago
Question 5 (5 points)
Dima020 [189]

Answer:

They Are all O's/oberavtions, because inference is using facts and reasoning, which is not the case here.

Explanation:

6 0
2 years ago
Read 2 more answers
An empty water bottle is full of air at 15°C and standard pressure. The volume of the bottle is 0. 500 liter. How many moles of
drek231 [11]

The moles of gas in the bottle has been 0.021 mol.

The ideal gas has been given as the gas where there has been negligible amount of interatomic collisions. The ideal gas equation has been given as:

PV=nRT

<h3>Computation for the moles of gas</h3>

The gi<em>ve</em>n gas has standard pressure, P=1\rm atm

The volume of the gas has been, V= 0. 500 \;\rm  L

The temperature of the gas has been, T=15^\circ \text C\\&#10;T=288\;\rm K

Substituting the values for the moles of gas, <em>n:</em>

<em />

<em />\rm 1\;\times\; 0. 500 =\textit n\;\times\;0.08214\;atm.L/mol.K\;\times\;288\;K\\\\&#10;\textit n=\dfrac{0. 500}{0.08214\;\times\;288} \;mol\\\\&#10;\textit n=0.021\;mol

The moles of gas in the bottle has been 0.021 mol.

Learn more about ideal gas, here:
brainly.com/question/8711877

5 0
2 years ago
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