D is the answer
Velocity maybe negative or positive
while speed is always positive
That depends on a few things that you haven't told us about the setup.
So I'm going to assume one of them, and then give you the answer
in terms of another one:
-- Assume a Class-I lever . . . the fulcrum is between the load and the effort.
-- Then the effort needed to lift the load is
(the weight of the load) x (13 / the distance between the fulcrum and the effort)
W = KE = 1/2m(v2f-v2i) also known as D just took the test
Answer:
7.3 newtons to the west
Explanation:
3.7kg × 11a - 3.7kg × ? = 3.7n
Answer:
a. 150 N
Explanation:
Gravitational Force: This is the force that act on a body under gravity.
The gravitational force always attract every object on or near the earth's surface. The earth therefore, exerts an attractive force on every object on or near it.
The S.I unit of gravitational force is Newton(N).
Mathematically, gravitational force of attraction is expressed as
(i) F = GmM/r² ........................ Equation 1 ( when it involves two object of different masses on the earth)
(ii) F = mg ............................... Equation 2 ( when it involves one mass and the gravitational field).
Given: m = 17 kg, g = 8.8 m/s²
Substituting into equation 2,
F = 17(8.8)
F = 149.6 N
F ≈ 150 N.
Thus the gravitational force = 150 N
The correct option is a. 150 N
