HELP ASAP! Chemical reactions involving liquids only will be influenced by ALL of the following EXCEPT: a) temperature of the sy
1 answer:
<span>Chemical reactions involving only liquids will be influenced by ALL of the following EXCEPT: </span><span><span>c) size of reactant particles d) pressure of the system.
</span>Reason:
1) As per Arrhenius theory, rate of chemical reactions is influence by temperature. Mathematically it is expressed as: k = A exp(-Ea/RT)
</span>where, k = rate constant, A = collision frequency, Ea = activation energy, T = temp. From above relation, it can be seen that, chemical reactions involving only liquids will be influenced temperature.
2) Also, if know that, rates of chemical reactions is mathematically expressed as:![Rate = [A]^{x} B^{y}....](https://tex.z-dn.net/?f=%20Rate%20%3D%20%5BA%5D%5E%7Bx%7D%20B%5E%7By%7D....%20%20)
,
where A, B, .. are the reactants.
From above relation, it can be seen that, chemical reactions involving only liquids will be influenced concentration i.e. number of particle.
3) However, since all the reactant and catalyst used (if any) is in liquid state, particle size of same will not influence the reaction.
4) Also, since there are no gas-phase reactant, pressure will not affect the reaction.
</span>Reason:
1) As per Arrhenius theory, rate of chemical reactions is influence by temperature. Mathematically it is expressed as: k = A exp(-Ea/RT)
</span>where, k = rate constant, A = collision frequency, Ea = activation energy, T = temp. From above relation, it can be seen that, chemical reactions involving only liquids will be influenced temperature.
2) Also, if know that, rates of chemical reactions is mathematically expressed as:
where A, B, .. are the reactants.
From above relation, it can be seen that, chemical reactions involving only liquids will be influenced concentration i.e. number of particle.
3) However, since all the reactant and catalyst used (if any) is in liquid state, particle size of same will not influence the reaction.
4) Also, since there are no gas-phase reactant, pressure will not affect the reaction.
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The molecular formulas of the empirical ones of P₂O₅ and CH₂O are P₄O₁₀ and C₇H₁₄O₇, respectively, knowing that their molar masses are 310 and 200.18 g/mol, respectively.
<h3>1. Molecular formula of P₂O₅</h3>We can calculate the molecular formula as follows:
(1)
Where:
- MF: is the molecular formula
- EF: is the empirical formula
- n: is an integer
To calculate the integer <em>n</em>, we need to use the following equation:
(2)
Where:
- M: is the molar mass of P₂O₅ = 310 g/mol
: is the molar mass of the empirical formula
The molar mass of the empirical formula of P₂O₅ is given by:
Where:
: is the atomic weight of phosphorus = 30.974 g/mol
: is the <em>atomic weight</em> of oxygen = 15.999 g/mol
So, the <em>molar mass</em> of the <em>empirical formula</em> of P₂O₅ is:
Now, we can find the integer <em>n </em>(eq 2).
Finally, after multiplying the integer <em>n</em> by the number of atoms on the empirical formula of P₂O₅, we have (eq 1):
Therefore, the molecular mass of P₂O₅ is P₄O₁₀.
<h3>2. Molecular formula of CH₂O </h3>We know:
- M: molar mass of CH₂O = 200.18 g/mol
To calculate the integer <em>n</em> and so the molecular mass of the molecule, we need to calculate the<em> molar mass</em> of the <em>empirical formula</em> of CH₂O.
Now, the integer <em>n </em>is equal to (eq 2):
Finally, the molecular formula of the molecule is (eq 1):
Therefore, the molecular formula of CH₂O is C₇H₁₄O₇.
Learn more about molecular formula here:
I hope it helps you!