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2 years ago

What is the electron structure of nitrogen?

Chemistry

2 answers:

Molodets [167]2 years ago

7 0

1s22s22p3 considering N is the third element in the 2nd P sublevel

adelina 88 [10]2 years ago

3 0

Answer : The correct option is, $1s^22s^22p3$

Explanation :

Electronic configuration : It is defined as the arrangement of the electrons of an atom in an atomic orbital.

The given element is, nitrogen.

The nitrogen element belongs to group 15 and the atomic number of nitrogen is 7.

As we know that the number of electrons is equal to the number of atomic number.

The number of electrons present in nitrogen = 7

Thus, the electronic configuration of nitrogen is, $1s^22s^22p3$

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What Element am I?

rjkz [21]

Answer:

The correct answer is - sulfur.

Explanation:

In the periodic table, there are 18 groups and 7 rows or periods arranged according to their atomic number or electronic configuration. In the question, it is mentioned that the desired element atomic mass is less than the atomic mass of the selenium which is 78.96, and more than oxygen which is 15.99 with 6 electron valence and present in the third row.

As it has 6 valency of electron it must be in the 16 group of the table that comprises the 6 valency and as it is located in the 3rd row it must be sulfur that also has an atomic mass between selenium and oxygen.

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2 years ago

Given the formulas for the ionic compounds, draw the correct ratio of cations to anions (a) BaSO4, (b) CaF2, (c) Mg3N2, (d) K2O.

Karolina [17]

Answer:

A. It formed by barium(Ba+2) ion and sulfate ( SO42- )

B. It is formed by calcium ion (Ca+2) and two fluoride ions (2F-)

C. It is formed by magnesium ion (Mg+2) and nitride ion (N3-)

D. It is formed by two potassium ions (2 K+) and oxide ion(O2-)

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2 years ago

A sample of argon gas at 55°C is under 845 mm Hg pressure. What will the new temperature be if the pressure is raised to 1050 mm

Maurinko [17]

Answer:

The final temperature at 1050 mmHg is 134.57 $^{\circ}C$ or 407.57 Kelvin.

Explanation:

Initial temperature = T = 55 $^{\circ}C$ = 328 K

Initial pressure = P = 845 mmHg

Assuming final to be temperature to be T' Kelvin

Final Pressure = P' = 1050 mmHg

The final temperature is obtained by following relation at constant volume

$\displaystyle \frac{P}{P'}=\displaystyle \frac{T}{T'} \\ \displaystyle \frac{845 \textrm{ mmHg}}{1050 \textrm{ mmHg}} = \displaystyle \frac{328 \textrm{ K}}{T'} \\T' = 407.57 \textrm{ Kelvin}$

The final temperature is 407.57 K

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