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Alex17521 [72]
3 years ago
13

What is the electron structure of nitrogen?

Chemistry
2 answers:
Molodets [167]3 years ago
7 0

1s22s22p3 considering N is the third element in the 2nd P sublevel

adelina 88 [10]3 years ago
3 0

Answer : The correct option is, 1s^22s^22p3

Explanation :

Electronic configuration : It is defined as the arrangement of the electrons of an atom in an atomic orbital.

The given element is, nitrogen.

The nitrogen element belongs to group 15 and the atomic number of nitrogen is 7.

As we know that the number of electrons is equal to the number of atomic number.

The number of electrons present in nitrogen = 7

Thus, the electronic configuration of nitrogen is, 1s^22s^22p3

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Answer:

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Explanation:

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3 years ago
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Which conversion factor correctly shows the relationship between moles and representative particles?
strojnjashka [21]
This is given by Avogagro number: 1 mol = 6.02*10^23 particles

Then you can do whichever to these two relations, because they are equivalent:

- 1mol / 6.02*10^23 representative particles, and
- 6.02*10^23 representative particle /1 mol

Only the second option of the question includes one of the valid conversion factors. Then, the conversion factor of the second option is the right answer
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Vesna [10]
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6 0
3 years ago
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How many moles of liquid water must freeze to remove 100 kJ of heat? (ΔHf = –334 J/<br> g.
Juliette [100K]
First figure out how many grams must freeze and then convert the grams to moles. 
<span>Hf = -334 J/g. Convert this to KJ/g by dividing by 1000. (There are 1000 Joules in a kJ). </span>
<span>Hf = -334 J/g ÷ 1000 J/kj = -0.334 kJ/g </span>
<span>Now, divide 100 kJ by -0.334 kJ/g (see how the units are lining up?) </span>
<span>100 kJ ÷ -0.334 kJ/g = 299 g </span>
<span>Now convert this to moles by dividing by the molecular weight of water (18.0g/mole). </span>
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5 0
3 years ago
A specific brand of gourmet chocolate candy contains 7.00 g of dietary fat in each 22.7-gpiece. How many kilograms of dietary fa
Genrish500 [490]

Answer:  0.14 kg

Explanation:

Gourmet chocolate candy contains 7.00 g of dietary fat in each 22.7-g piece

That is 1 piece of candy weighs 22.7 g and contains 7.00 g of dietary fat

Converting the mass in pounds to kg  

1 lb = 0.45 kg = 450 grams    (1kg=1000g)

Number of pieces = \frac{450}{22.7g}=20pieces

1 piece contains = 7 g of dietary fat

Thus 30 pieces would contain =\frac{7}{1}\times 20=140g of dietary fat

1 g = 0.001 kg

Thus 140 grams =\frac{0.001}{1}\times 140=0.14kg

Thus 0.14 kg of dietary fat are in a box containing 1.00 lb of candy.

5 0
3 years ago
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