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vodka [1.7K]
3 years ago
9

What is the name of the chemical formula Ti3(PO4)2

Chemistry
1 answer:
Veseljchak [2.6K]3 years ago
3 0
It is Titanium (II) Phosphate.
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Which property is true for metals
san4es73 [151]

most metals conduct electricity and are very dull to the look. most metals are toxic if eaten and are hard.

aluminum is a type of metal they is softer than the opther and conducts eletricty like a boss.

nickel on the opther hand is also a metal but does not conduct a lot of electricy.

metals can be bent and others can break,

6 0
3 years ago
Read 2 more answers
4. DBearded waste of Co-60 must be stored until it is no longer radioactive. Cobalt-60
Bingel [31]

464 g radioisotope was present when the sample was put in storage

<h3>Further explanation</h3>

Given

Sample waste of Co-60 = 14.5 g

26.5 years in storage

Required

Initial sample

Solution

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

t = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

Half-life of Co-60 = 5.3 years

Input the value :

\tt 14.5=No.\dfrac{1}{2}^{26.5/5.3}\\\\14.5=No.\dfrac{1}{2}^5\\\\No=\boxed{\bold{464~g}}

8 0
2 years ago
An archer pulls her bowstring back 0.370 m by exerting a force that increases uniformly from zero to 264 N. (a) What is the equi
Arte-miy333 [17]

Answer:

713.51 N/m

Explanation:

Hook's Law: This law states that provided the elastic limit is not exceeded, the extension in an elastic material is directly proportional to the applied force.

From hook's law,

F = ke ...........................Equation 1

Where F = Force exerted on the bowstring, e = Extension/compression of the bowstring, k = Spring constant of the bow.

Make k the subject of the equation,

k = F/e ............................ Equation 2

Given: F = 264 N, e = 0.37 m.

Substitute into equation 2

k = 264/0.37

k = 713.51 N/m

Hence the spring constant of the bow  = 713.51 N/m

3 0
2 years ago
A sample of magnesium oxide has a mass of 94.4 g. How many molecules
ella [17]

Answer: 1.414x10^24 molecules in 94.4g MgO

Explanation: molar mass MgO 40.204

molecules in 40.204 g MgO = avogadro number

molecules in 94.4 g MgO = (94.4/40.204)*avogadro number

(94.4/40.204)*6.02214076*10^23 = 14.14x10^23

7 0
3 years ago
Is density a chemical or physical property of a substance?
pychu [463]

Answer:

A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance. Physical properties include color, density, hardness, and melting and boiling points. A chemical property describes the ability of a substance to undergo a specific chemical change.

I hope this helps you understand! <3

8 0
2 years ago
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