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zavuch27 [327]
4 years ago
6

A balloon containing a sample of helium gas measures 1.50 L at a temperature of 25.0°C is placed in a refrigerator at 36.0°F. Ca

lculate its new volume. Enter your answer in the box provided.
Chemistry
1 answer:
Fiesta28 [93]4 years ago
6 0

Answer:

1,39 L

Explanation:

Charle's Law states that the volume of a fixed amount of gas <em>maintained at constant pressure</em> is directly proportional to the<u> absolute temperature</u> of the gas, for a constant amount of gas we can write:

\frac{V1}{T1}=\frac{V2}{T2}

As the pressure of the balloon doesn't change, we can use Charle's Law to solve the problem. Firs we change the given temperatures to absolute temperature units ( °K), using the following relations:

°K=273+°C

°K=5/9(°F-32)+273

Therefore:

V1=1.5 L, T1=273+25=298°K

V2=?,      T2=5/9(36-32)+273=275,2°K

V2=\frac{V1T2}{T1}=\frac{275,2*1,5}{298}=1,39L

The new volume of the balloon is 1,39 L.

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Since there is no sample, let us assume 100 g of the solution: 
(22.2% of 100 g) / (46.0254 g HCOOH/mol) = 0.48234 mol HCOOH 
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