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zavuch27 [327]
3 years ago
6

A balloon containing a sample of helium gas measures 1.50 L at a temperature of 25.0°C is placed in a refrigerator at 36.0°F. Ca

lculate its new volume. Enter your answer in the box provided.
Chemistry
1 answer:
Fiesta28 [93]3 years ago
6 0

Answer:

1,39 L

Explanation:

Charle's Law states that the volume of a fixed amount of gas <em>maintained at constant pressure</em> is directly proportional to the<u> absolute temperature</u> of the gas, for a constant amount of gas we can write:

\frac{V1}{T1}=\frac{V2}{T2}

As the pressure of the balloon doesn't change, we can use Charle's Law to solve the problem. Firs we change the given temperatures to absolute temperature units ( °K), using the following relations:

°K=273+°C

°K=5/9(°F-32)+273

Therefore:

V1=1.5 L, T1=273+25=298°K

V2=?,      T2=5/9(36-32)+273=275,2°K

V2=\frac{V1T2}{T1}=\frac{275,2*1,5}{298}=1,39L

The new volume of the balloon is 1,39 L.

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So, for stoichiometry, we always start with our "given". In this case, it would be the 10.0 grams of NaHCO3. This unit always goes over 1.

So, our first step would look like this:

10.0
------
  1

Next, we need to cancel out grams to get to moles. To do this, we will do grams of citric acid on the BOTTOM of the next step, so it cancels out. This unit in grams will be the mass of NaHCO3, which is 84.007. Then, we will do our unit of moles on top. Since this is unknown, it will be 1.

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