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irina [24]
3 years ago
5

A ball hits a wall. What is true about the magnitude of the force experienced by the ball compared with the force experienced by

the wall?
Physics
1 answer:
Ivahew [28]3 years ago
5 0
<span>This is best understood with Newtons Third Law of Motion: for every action there is an equal and opposite reaction. That should allow you to see the answer.</span>
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Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial spe
sattari [20]
I can't make sense of this question. Julie's throwing the ball, so it's leaving her rather than arriving at her ???
3 0
3 years ago
How does the time at which you see things happen at a baseball game compare to the time when you hear things happen? Explain you
hoa [83]

Answer:

Because of the speed of the sound.

Explanation:

The first thing that happens in such cases is to take into account the speed of the sound. First, we see that the player hits the ball with the bat, if we are in the stands far enough we will hear the sound of the batting time later, this time depends on the speed of the sound which is equal to 345 [m/s].

Another visible and practical example is a fireworks display, where people nearby immediately hear the explosion. while those at a great distance will be able to see first the explosion followed by the sound.

With the following equation, we can calculate how long it takes to hear a hit or explosion

t = x / v

where:

x = distance [m]

v = sound velocity = 345 [m/s]

t = time [s]

7 0
3 years ago
Which Box in the diagram above, should this picture go into?
lyudmila [28]
What diagram? There isn’t one
7 0
3 years ago
g An airplane is flying through a thundercloud at a height of 1500 m. (This is a very dangerous thing to do because of updrafts,
Stolb23 [73]

Answer:

523269.9\ \text{N/m}

Explanation:

q = Charge

r = Distance

q_1=25\ \text{C}

r_1=3000\ \text{m}

q_2=40\ \text{C}

r_2=850\ \text{m}

The electric field is given by

E=E_1+E_1\\\Rightarrow E=k(\dfrac{q_1}{r_1^2}+\dfrac{q_2}{r_2^2})\\\Rightarrow E=9\times 10^9\times (\dfrac{25}{3000^2}+\dfrac{40}{850^2})\\\Rightarrow E=523269.9\ \text{N/m}

The electric field at the aircraft is 523269.9\ \text{N/m}

4 0
3 years ago
Pls help me quickly ......​
marishachu [46]

Answer:

the last one: weight force

3 0
3 years ago
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