A large uniform chain is hanging from the ceiling, supporting a block of mass 46 kg. The mass of the chain itself is 19 kg, and
1 answer:
Answer:
T = 451.26 N
Explanation:
It is given that,
The mass of block, m = 46 kg
Mass of the chain, m' = 19 kg
Length of the chain, l = 1.9 m
Let T is the the tension in the chain at the point where the chain is supporting the block. It is clearly equal to the product of mass and acceleration.
T = 451.26 N
So, the tension in the chain at the point where the chain is supporting the block is 451.26 N. Hence, this is the required solution.
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Answer:
Time = t = 6.62 s
Explanation:
Given data:
Height = h = 215 m
Initial velocity = = 0 m/s
gravitational acceleration = g = 9.8 m/s²
Time = t = ?
According to second equation of motion
As initial velocity is zero, So the first term of right hand side of above equation equal to zero.
t² =
t =
t =
t = 6.62 s