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2 years ago

8

We can determine the __________ of a wave when given the frequency and the wavelength. (2 points)

2 answers:

poizon [28]2 years ago

6 0

It's velocity because you need the velocity of a wave to determine the other aspects of a wave and to calculate the velocity of a wave you need to multiply the frequency x wavelength to get the velocity of a wave.

Olin [163]2 years ago

3 0

The correct answer to the problemis velocity. I did the test.

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The most pressing problem in the Chesapeake Bay is

densk [106]

Answer:

The answer is C. Pollution

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2 years ago

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A bowler throws a bowling ball of radius R = 11 cm down the lane with initial speed v₀ = 7.5 m/s. The ball is thrown in such a w

salantis [7]

Answer:

a) t = 0.74s

b) D = 4.76m

c) Vf = 5.35m/s

Explanation:

The ball starts rolling when Vf = ωf*R.

We know that:

Vf = Vo - a*t

ωf = ωo + α*t

With a sum of forces on the ball:

$Ff = m*a$

$\mu*N = m*a$

$\mu*m*g = m*a$

$a=\mu*g=2.9m/s^2$

With a sum of torque on the ball:

$Ff*R = I*\alpha$

$\mu*m*g*R = 2/5*m*R^2*\alpha$

$\alpha=5/2*\mu*g/R=65.9rad/s^2$

Replacing both accelerations:

$Vo - a*t=\alpha*t*R$

$7.5 - 2.9*t=65.9*t*0.11$

t=0.74s

The distance will be:

$D = Vo*t-1/2*a*t^2$

$D = 4.76m$

Final velocity:

$Vf=Vo-a*t$

Vf=5.35m/s

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2 years ago

There's an electric field in some region of space that doesn't change with position. An electron starts moving with a speed of 2

tangare [24]

Answer:

Explanation:

Given

speed of Electron $u=2\times 10^7\ m/s$

final speed of Electron $v=4\times 10^7\ m/s$

distance traveled $d=1.2\ cm$

using equation of motion

$v^2-u^2=2as$

where v=Final velocity

u=initial velocity

a=acceleration

s=displacement

$(4\times 10^7)^2-(2\times 10^7)^2=2\times a\times 1.2\times 10^{-2}$

$a=5\times 10^{16}\ m/s^2$

acceleration is given by $a=\frac{qE}{m}$

where q=charge of electron

m=mass of electron

E=electric Field strength

$5\times 10^{16}=\frac{1.6\times 10^{-19}\cdot E}{9.1\times 10^{-31}}$

$E=248.3\ kN/C$

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3 years ago

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kirza4 [7]

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2 years ago

An airplane wing is designed so that the speed of the air across the top of the wing is 255 m/s when the speed of the air below

grin007 [14]

<h2>Answer:442758.96N</h2>

Explanation:

This problem is solved using Bernoulli's equation.

Let $P$ be the pressure at a point.

Let $p$ be the density fluid at a point.

Let $v$ be the velocity of fluid at a point.

Bernoulli's equation states that $P+\frac{1}{2}pv^{2}+pgh=constant$ for all points.

Lets apply the equation of a point just above the wing and to point just below the wing.

Let $p_{up}$ be the pressure of a point just above the wing.

Let $p_{do}$ be the pressure of a point just below the wing.

Since the aeroplane wing is flat,the heights of both the points are same.

$\frac{1}{2}(1.29)(255)^{2}+p_{up}= \frac{1}{2}(1.29)(199)^{2}+p_{do}$

So, $p_{up}-p_{do}=\frac{1}{2}\times 1.29\times (25424)=16398.48Pa$

Force is given by the product of pressure difference and area.

Given that area is $27ms^{2}$ .

So,lifting force is $16398.48\times 27=442758.96N$

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3 years ago