Well the square root of a number is a number times its self equaling the number you're getting the square root of. For example:
<span>√ 25
</span>
To get sqrt of 25 we need to find a number times its self that equals 25. Lets try 8.
8 x 8 = 64
Well thats much too high, We'll try a lower number.
4 x 4 = 16
Just a little higher.
5 x 5 = 25
Since 5 times itself equals 25 that makes it the sqrt.
So, the √ 25 is 5.
Mukat gets 40, Usha gets 8
Step-by-step explanation:
Mukat = 5 × Usha
After Mukat gives Usha 16 books ,Usha gets (16 + initial number of books) and Mukat gets (5 × Usha - 16)
Then Mukat = final number of books for Usha
5 × Usha - 16 = Usha + 16
(5 × Usha ) - Usha = 16+16
4 × Usha = 32
Usha = 8 i.e her number of books.
Mukat = 5×8=40.
I HOPE IT'S OK
Answer:
What we are going to do for this case is find the cost for each case:
Cost to run the car before the mechanic worked on it:
Cost to run the car after the mechanic worked on it:
The difference between both cases is:
Answer:
It cost to run the car after the mechanic worked on it 0.01 $ / mile less than before the mechanic worked on it.
Read more on Brainly.com - brainly.com/question/2528459#readmoreStep-by-step explanation:
Answer:
x = 2 11/12
Step-by-step explanation:
Multiply the equation by 12. This eliminates fractions.
... 12 -12x -28 = 12x +27 -36x -8
Collect terms.
... -16 -12x = -24x +19
Add 24x+16
... 12x = 35
Divide by the coefficient of x
... x = 35/12 = 2 11/12
Answer:
- r(0) = <0, 100> . . . . . . . .meters
- r'(0) = <7.071, 7.071> . . . . meters per second
Step-by-step explanation:
<u>Initial Position</u>
The problem statement tells us we're measuring position from the ground at the base of the building where the projectile was launched. The initial horizontal position is presumed to be zero. The initial vertical position is said to be 100 meters from the ground, so (in meters) ...
r(0) = <0, 100>
<u>Initial Velocity</u>
The velocity vector resolves into components in the horizontal direction and the vertical direction. For angle α from the horizontal, the horizontal component of velocity is v₁·cos(α), and the vertical component is v₁·sin(α). For v₁ = 10 m/s and α = π/4, the initial velocity vector (in m/s) is ...
r'(0) = <10·cos(π/4), 10·sin(π/4)>
r'(0) ≈ <7.071, 7.071>
