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skelet666 [1.2K]
3 years ago
13

-6<2c-4<14 compound inequality​

Mathematics
1 answer:
Vladimir [108]3 years ago
8 0

Answer:

-1 < c < 9

Step-by-step explanation:

-6<2c-4<14

Add 4 to all sides

-6+4<2c-4+4<14+4

-2<2c<18

Divide by 2

-2/2<2c/2<18/2

-1 < c < 9

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Which comparison is true?<br><br> 38=36<br><br> 38&lt;36<br><br> 38&gt;36
mylen [45]

Answer:

38 > 36

it is true it shows that 38 is greater than 36

6 0
2 years ago
Carolyn has 9 quarters, 4 dimes, 7 nickels, and 2 pennies. Write and evaluate the expression to determine how much money she has
zlopas [31]

Answer:

3.02

Step-by-step explanation:

quarters are .25

dimes are .10

nickels are .05

pennies are .01

9 * .25 + 4 * .10 + 7 *.05 + 2 *.01

2.25+0.4+0.35+0.02

3.02

7 0
3 years ago
Bula went to Target and bought a new jacket. The price tag said $85 but the sign on the rack said
madreJ [45]
85 * 0.20 = 17
85 - 17 = $68
He paid $68 for the jacket
6 0
3 years ago
Read 2 more answers
Assume that a policyholder is four times more likely to file exactly two claims as to file exactly three claims. Assume also tha
kykrilka [37]

Answer:

1.3125

Step-by-step explanation:

Given that our random variable X follows a Poisson distributionP(X=k)=\frac{\lambda^k e^-^p}{k!} \ \ \ \ \ \ \ \ p=\lambda

Evaluate the formula at k=2,3:

P(X=2)=0.5\lambda^2e^{-\lambda}\\\\P(X=3)=\frac{1}{6}\lambda^2e^{-\lambda}

#since

4P(X=2)=P(X=3);\\\\0.5\lambda^2e^{-\lambda}=4\times\frac{1}{6}\lambda^3e^{-\lambda}\\\\0.5\lambda^2=\frac{2}{3}\lambda^3\\\\0.75=\lambda

The mean and variance of the Poisson distributed random variable is equal to \lambda:

\mu=\lambda=0.75\\\sigma ^2=\lambda=0.75

#By property variance:

\sigma ^2=V(X)=E(X^2)-(E(X))^2=E(X^2)\\\\E(X^2)=\sigma^2+\mu^2=0.75+0.75^2=1.3125

The expectation is 1.3125

4 0
3 years ago
Find all the factor pairs for 84 and complete the equations.
VMariaS [17]
1. 84 = 1 x 84

2. 84 = 2 x 42

3. 84 = 3 x 28

4. 84 = 4 x 21

5. 84 = 6 x 14

6. 85 = 7 x 12


Hope this helps!
5 0
3 years ago
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