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lara31 [8.8K]
3 years ago
6

A mobile travels 98 km in 2h calculate: a) your speed b) how many kilometers will you travel in 3h with the same speed?

Physics
1 answer:
ra1l [238]3 years ago
6 0
If you are traveling 98 km in 2h you are traveling 49 km/h (98/2=49).
To calculate how many kilometers you will travel in 3 hours, multiply 49 (the number of kilometers) times 3 (the number of hours) and you get 147 kilometers.

Hope that helps.
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19.A 20 kg sign is pulled by a horizontal force such that the single rope (originally vertical) holding the sign makes an angle
Andreyy89

Answer:

A)T=209.94N

B) F=75.24N

Explanation:

Using the free body diagram and according to Newton's first law, we have:

\sum F_y=Tcos(21^\circ)-mg=0(1)\\\sum F_x=F-Tsin(21^\circ)=0(2)

A) Solving (1) for T:

T=\frac{mg}{cos(21^\circ)}\\T=\frac{20kg(9.8\frac{m}{s^2})}{cos(21^\circ)}\\T=209.94N

B) Solving (2) for F:

F=Tsin(21^\circ)\\F=(209.94N)sin(21^\circ)\\F=75.24N

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3 years ago
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B. A film of food wrap. The cell membrane is the outermost layer that is protecting the cell
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Is this true or false ethics deals with morals and values and can be measured and tested using the scientific method.
sammy [17]

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3 0
3 years ago
Read 2 more answers
A reservoir located in the mountain 250 m above sea level flows through a pipe to a hydroelectric plant in a town at sea level.
Pavlova-9 [17]

Answer:

     v₂ = 70 m / s

Explanation:

For this exercise let's use Bernoulli's equation

where subscript 1 is for the top of the mountain and subscript 2 is for Tuesday's level

 

          P₁ + ½ ρ v₁² + ρ g y₁ = P₂ +1/2 ρ v₂² + ρ g y₂

indicate that the pressure in the two points is the same, y₁ = 250 m, y₂ = 0 m, the water in the upper part, because it is a reservoir, is very large for which the velocity is very small, we will approximate it to 0 (v₁ = 0), we substitute

         ρ g y₁ = ½ ρ v₂²

         v₂ = \sqrt {2g \ y_1}

let's calculate

         v₂ = √( 2 9.8 250)

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6 0
3 years ago
An electron with a speed of 0.95c is emitted by a supernova, where cc is the speed of light. What is the magnitude of the moment
krok68 [10]

Answer:

2.59×10¯²² Kgm/s

Explanation:

Data obtained from the question include:

Velocity of electron = 0.95c

Momentum =?

Next, we shall determine the velocity of the electron. This can be obtained as follow:

Velocity of electron = 0.95c

Velocity of Light (c) = 3×10⁸ m/s

Velocity of electron = 0.95c

Velocity of electron = 0.95 × 3×10⁸

Velocity of electron = 2.85×10⁸ m/s

Finally, we shall determine the mometum of the electron.

Momentum is simply defined as the product of mass and velocity. Mathematically, it is expressed as:

Momentum = mass x Velocity

Thus, with the above formula, we calculate the momentum of the electron as follow:

Mass of electron = 9.1×10¯³¹ Kg

Velocity of electron = 2.85×10⁸ m/s

Momentum of electron =?

Momentum = mass x Velocity

Momentum = 9.1×10¯³¹ × 2.85×10⁸

Momentum = 2.59×10¯²² Kgm/s

Therefore, the momentum of the electron is 2.59×10¯²² Kgm/s

3 0
3 years ago
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