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3 years ago

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Which government agency is responsible for protecting the nation’s transportation systems to ensure freedom of movement for pass

engers and commerce? A. Environmental Protection Agency B. Federal Communications Commission C. Occupational Safety and Health Administration D. Transportation Security Administration
economics high school level.

2 answers:

sergij07 [2.7K]3 years ago

7 0

The correct answer is D. Transportation Security Administration.

-Willow I know U might not bealive me but I am Correct.

And here Is my Proof. They are an agency that organizes numerous things that are related to transportation security. Among other things, they regulate things such as quality of roads or railroads, or they participate in establishing safety standards for various types of vehicles, from cars to boats and airplanes and trucks, and they do various other things.

emmasim [6.3K]3 years ago

4 0

i'd say A but it still could be wrong, but anyways hello...?

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A cannonball is launched from the ground at an angle of 30 degrees above the horizontal and a speed of 30 m/s. Ideally (no air r

marusya05 [52]

As we know that here no air resistance while ball is moving in air

So here we will say that

initial total energy = final total energy

$KE_i + U_i = KE_f + U_f$

here we know that

$Ui = U_f = 0$ (as it will be on ground at initial and final position)

so we will say

$KE_i = KE_f$

since mass is always conserved

so we will say that final speed of the ball must be equal to the initial speed of the ball

so we have

$v_f = v_i = 30 m/s$

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3 years ago

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A 1.1-kg uniform bar of metal is 0.40 m long and has a diameter of 2.0 cm. When someone bangs one end of this bar, a 1.5 MHz sho

lyudmila [28]

Answer:

$\lambda = 2.22\times 10^{-3}\ m$

Explanation:

Given,

mass of the bar = 1.1 Kg

length of rod, l = 0.40 m

diameter of the rod, d = 2 cm

frequency, f = 1.5 MHz

time, t = 0.12 ms

wavelength of the shock wave = ?

Speed of the wave = $\dfrac{L}{t}=\dfrac{0.40}{0.12\times 10^{-3}}$

v = 3333.33 m/s

wavelength of the wave

$\lambda = \dfrac{v}{f}= \dfrac{3333.33}{1.5\times 10^6}$

$\lambda = 2.22\times 10^{-3}\ m$

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2 years ago

Can someone with an IQ score of 120 be gifted? Based on psychological thought, explain why or why not and give an example. ILL M

Pani-rosa [81]

Hello!

Yes, someone with an IQ score of 120 can be gifted.

An IQ score of 120 means that the individual is moderately gifted. Although this IQ doesn't qualify for gifted education programs, research shows that people with IQs of about 145-180 don't perform significantly better than people with 120s IQ in terms of success.

As an example, professor Dean Simonton from the University of California found that an optimum leader should have an IQ in the 120-125 range, so having an IQ of 120 would mean that the individual is gifted for leadership.

Have a nice day!

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2 years ago

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Which letter represents the wavelength of the wave?<br><br>A: a<br><br>B: b<br><br>C: c<br><br>D: d

KATRIN_1 [288]

Answer:

D

Explanation:

Shows the distance between each new wave.

4 0

3 years ago

Read 2 more answers

Please help i forgot how to solve this, thank you.

mixas84 [53]

Answer:

The radius of its orbit is $R \approx 1.899\times 10^{9}\,m$ .

Explanation:

Let suppose that Callisto rotates around Jupiter in a circular path and at constant speed, then we understand that net acceleration of this satellite is equal to the centripetal acceleration due to gravity of Jupiter. That is:

$\omega^{2}\cdot R = a_{net}$ (1)

Where:

$\omega$ - Angular speed, measured in radians per second.

$R$ - Radius of the orbit, measured in meters.

$a_{net}$ - Net acceleration, measured in meters per square second.

In addition, angular speed can be described in terms of period ( $T$ ), measured in seconds:

$\omega = \frac{2\pi}{T}$ (2)

And the net acceleration by the Newton's Law of Gravitation:

$a_{net} = \frac{G\cdot m}{R^{2}}$ (3)

Where:

$G$ - Gravitation constant, measured in cubic meters per kilogram-square second.

$m$ - Mass of Jupiter, measured in kilograms.

Now we apply (2) and (3) in (1) to derive an expression for the radius of the orbit:

$\frac{4\pi^{2}\cdot R}{T^{2}} = \frac{G\cdot m}{R^{2}}$

$R^{3} = \frac{G\cdot m \cdot T^{2}}{4\pi^{2}}$

$R = \sqrt[3]{\frac{G\cdot m\cdot T}{4\pi^{2}} }$ (4)

If we know that $G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}$ , $m = 1.90\times 10^{27}\,kg$ and $T = 1460160\,s$ , then the radius of the orbit of Callisto is:

$R = \sqrt[3]{\frac{(6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} )\cdot (1.90\times 10^{27}\,kg)\cdot (1460160\,s)^{2}}{4\pi^{2}} }$

$R \approx 1.899\times 10^{9}\,m$

8 0

2 years ago