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puteri [66]
2 years ago
5

Fish, amphibians, reptiles, birds, and mammals have similar embryos. They all start with gill slits. Fish and some amphibians gr

ow to have gills. Some amphibians, reptiles, birds, and mammals develop lungs to breathe air
They all start with tails. Fish, some amphibians, reptiles, and birds grow tails. Humans do not keep their tails.
Fish and reptiles develop scales. Amphibians, birds, and humans have skin. Birds have feathers, and humans have hair. With which animal do humans exhibit the most linear relationship?
birds
amphibians
reptiles
fish
Chemistry
1 answer:
Ilya [14]2 years ago
5 0

Answer:

Birds

Explanation: They are both mammals

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G determine the concentration of an hbr solution if a 45.00 ml aliquot of the solution yields 0.6485 g agbr when added to a solu
Sunny_sXe [5.5K]

The molecular weight of silver bromide (AgBr) is 187.77 g/mole. The presence of the ions in solution can be shown as- AgBr (insoluble) ⇄Ag^{+} + Br^{-1}.

45.00 mL of the aliquot contains 0.6485 g of AgBr. Thus 1000 mL of the aliquot contains \frac{0.6485}{45}×1000 = 14.411 gm-mole. Thus the solubility product K_{sp}of AgBr = [Ag^{+}]×Br^{-}.

Or, 5.0×10^{-13} = S^{2} (the given value of solubility product of AgBr is 5.0×10^{-13} and the charge of the both ions are same).

Thus S = (5.00×10^{-13})^{1/2} = 7.071×10^{-7} g/mL.

Thus the concentration of Br^{-1} or HBr is 7.071×10^{-7} g/mL.

4 0
3 years ago
Solutions of potassium iodide and lead(II)nitrate are mixed. The resulting lead
LenaWriter [7]
Answer is D
Balance the equation
6 0
2 years ago
Concentrated nitric acid used in laboratory work is 68% nitric acid by mass in aqueous solution. What should be the molarity of
dsp73
The first thing we need to do here is to recognize the unit of molarity and the units of the given percentage of nitric acid.

Molarity is mol HNO3 / L of solution. This is our aim

The given percentage is 0.68 g HNO3/ g solution

multiplying this with density to convert g solution into mL solution and dividing with the molecular weight of HNO3 (63 g/mol) to convert g HNO3 to mol. Therefore we obtain

0.016 mol/ mL or 16.23 mol/ L (M)

6 0
3 years ago
Please answer the “(fill-in)” ones thank you :)
Dovator [93]

Answer:

look

Explanation:

diffculte ou my good i need help too

8 0
3 years ago
What is the minimum number of moles of potassium permanganate that would be required to completely oxidize 1.0 moles of benzalde
makvit [3.9K]
Mole ratio :

<span>5 C</span>₆<span>H</span>₆<span>CHO + 2 KMnO</span>₄<span> + 6 H</span>⁺ <span>= 5 C</span>₆<span>H</span>₆<span>COOH + 2 Mn</span>²⁺<span> + 3 H</span>₂<span>O + 2 K</span>⁺

5 moles C₆H₆CHO ------------------ 2 moles KMnO₄
1.0 moles C₆H₆CHO ---------------- ( moles of KMnO₄ )

moles of KMnO₄ = 1.0 x 2 / 5

moles of KMnO₄ = 2 / 5

= 0.40 moles of KMnO4

hope this helps!


7 0
3 years ago
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