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ANTONII [103]
3 years ago
10

Answer quickly plz. CO2 dissolving in bodies of water forms_____

Chemistry
2 answers:
aivan3 [116]3 years ago
8 0

Answer:C. Carbonic Acid; decrease

Explanation:

Carbonic acid is formed and acid decrease pH

Art [367]3 years ago
5 0

CO2 dissolving in bodies of water forms carbonic acid which causes the pH to decrease.

Hope this helps! Please correct me if im wrong! :)

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Taking into account the definition of density, the mass of a substance with a volume of 150 cm³ and a density of 1.5 \frac{g}{cm^{3} }  is 225 grams.

<h3>What is density</h3>

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

<h3>Mass of the substance in this case</h3>

In this case, you know that:

  • Density= 1.5 \frac{g}{cm^{3} }
  • Volume= 150 cm³

Replacing in the definition of density:

1.5 \frac{g}{cm^{3} } =\frac{mass}{150 cm^{3} }

Solving:

mass= 1.5 \frac{g}{cm^{3} }  ×150 cm³

<u><em>mass= 225 g</em></u>

In summary, the mass of a substance with a volume of 150 cm³ and a density of 1.5 \frac{g}{cm^{3} }  is 225 grams.

Learn more about density:

brainly.com/question/952755

brainly.com/question/1462554

#SPJ1

7 0
2 years ago
Robert was changing the oil in his truck. He dumped the used oil on the ground in his yard. He didn't know it, but Robert was hu
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3 years ago
Read 2 more answers
A nitric acid solution (HNO3) has a molar concentration of 0.00044 M. Calculate the [H3O+],[OH-] and the pH of the solution. Rem
valentinak56 [21]

[H₃O⁺]=4.4 x 10⁻⁴

pH=3.357

[OH⁻] = 2.28 x 10⁻¹¹

<h3>Further explanation</h3>

Given

HNO3 concentration = 0.00044 M

Required

[H3O+],[OH-] and the pH

Solution

HNO₃ = strong acid

HNO₃ ⇒ H₃O⁺ + NO₃⁻

[H₃O⁺]=[HNO₃]=4.4 x 10⁻⁴

For strong acid pH=-log[H₃O⁺]

pH=-log 4.4 x 10⁻⁴ = 4-log 4.4 =3.357

pOH+pH=pKw

pOH+3.357=14

pOH=14-3.357=10.643

pOH=-log[OH⁻]

\tt [OH^-]=10^{-10.643}=2.28\times 10^{-11}

8 0
3 years ago
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