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IrinaK [193]
4 years ago
7

Engineering Careers Scavenger Hunt

Engineering
2 answers:
emmasim [6.3K]4 years ago
6 0

Answer:

c

Explanation:

it's the only engineering career

tia_tia [17]4 years ago
5 0
C is the only engineering career :)
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How would you increase the size of the base unit of length in the metric system
S_A_V [24]
The size of metric units increases tenfold as you go up the metric scale. The decimal system works the same way: a tenth is 10 times larger than a hundredth; a hundredth is 10 times larger than a thousandth, etc.
4 0
3 years ago
Excepted packaging refers to fiberboard boxes, sturdy wooden boxes, or steel crates that are designed to transport:
nika2105 [10]

Excepted packaging refers to fiberboard boxes, sturdy wooden boxes, or steel crates that are designed to transport materials with extremely low levels of radioactivity.

<h3>What is excepted packaging?</h3>

Excepted packaging can be defined as a type of box that is designed and developed for the transportation of materials with extremely low levels of radioactivity.

This ultimately implies that, a type of box which is strictly used for the transportation of materials with extremely low levels of radioactivity in order to prevent hazard.

Read more on packaging here: brainly.com/question/14985175

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5 0
2 years ago
What is the definition of a struck by injury
dmitriy555 [2]

Produced by forcible contact or impact between the injured person and an object or a piece of equipment

Explanation:

it mean you get injured after you've already been injured

3 0
3 years ago
Consider three charged sheets, A, B, and C. The sheets are parallel with A above B above C. On each sheet there is surface charg
babunello [35]

Answer:

0.

Explanation:

To find the electrical force per unit area on each sheet we start defining our variables,

\sigma_A = -4.10^{-5}C/m^2

\sigma_B= -7.10^{-5}C/m^2

\sigma_C = -3.1^{-5}C/m^2

We find the electric field for each one, this formula is given by,

E= \frac{\sigma_i}{2\epsilon_0}

Substituting each value from the three charged sheets, we have

E_A= \frac{-4.10^{-5}C/m^2}{2\epsilon_0}(\hat{j})

E_B= \frac{-7.10^{-5}C/m^2}{2\epsilon_0}(-\hat{j})

E_C= \frac{-3.1^{-5}C/m^2}{2\epsilon_0}(\hat{j})

The electric field is

E_{NET}= E_A+E_B+E_C

E_{NET}=\frac{-4.10^{-5}C/m^2}{2\epsilon_0}(\hat{j})+\frac{-7.10^{-5}C/m^2}{2\epsilon_0}(-\hat{j})+ \frac{-3.1^{-5}C/m^2}{2\epsilon_0}(\hat{j})

E_{NET} = 0

Force on each sheet is,

F=E_{NET}\sigma ds

F=0

The total force is 0

5 0
3 years ago
There are little to no benefits to supplementary field identification programs
VashaNatasha [74]

Answer:

True, supplementary field identification programs tend to limit the use of routine programs that target service delivery using routine systems.

Explanation:

When supplementary field identification programs are applied in a study, they have damaging effects to other systems and programs already in progress targeting certain/similar variables in a study group.Such programs are initiated to boost the already existing systems of programs that are in continuous application( routine basis). As a supplement , we expect more positive results in the rates per the variables included in a study.However, results has proved the opposite.For example, supplementary immunization activities applied in programs targeting demographic and health systems services reveled that such programs reduce the probability of receiving the services provided by other routine health systems conducting continuous vaccination programs to the target groups.

4 0
4 years ago
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