What speeds did john j montgomerys gliders reach

please how to drawing mechanical drawing after connecting the all parts thanks

rusak2 [61]

The answer would have to be 7

3 0

2 years ago

g a heat engine is located between thermal reservoirs at 400k and 1600k. the heat engine operates with an efficiency that is 70%

Bond [772]

Answer:

Heat rejected to cold body = 3.81 kJ

Explanation:

Temperature of hot thermal reservoir Th = 1600 K

Temperature of cold thermal reservoir Tc = 400 K

efficiency of the Carnot's engine = 1 - $\frac{Tc}{Th}$

eff. of the Carnot's engine = 1 - $\frac{400}{600}$

eff = 1 - 0.25 = 0.75

efficiency of the heat engine = 70% of 0.75 = 0.525

work done by heat engine = 2 kJ

eff. of heat engine is gotten as = W/Q

where W = work done by heat engine

Q = heat rejected by heat engine to lower temperature reservoir

from the equation, we can derive that

heat rejected Q = W/eff = 2/0.525 = 3.81 kJ

6 0

3 years ago

An ideal Diesel cycle has a maximum cycle temperature of 2000°C. The state of the air at the beginning of the compression is P1

IrinaVladis [17]

Answer:

Power produced = 90.47 KW

Explanation:

We are given;

R = 0.287 kJ/kg·K

T1 = 15°C = 15 + 273 = 288 K

P1 = 95 KPa

Number of cylinders;N_cyl = 8

Bore;B = 10cm = 0.1m

Stroke;S = 12cm = 0.12m

cp = 1.005 kJ/kg·K

cv = 0.718 kJ/kg·K

k = 1.4

First of all let's find the initial specific volume;

α1 = RT1/P1

α1 = 0.287 * 288/95

α1 = 0.87 m³/kg

Now, let's find the total mass of air from the formula;

m =(V•N_cyl)/α1 =(B²•N_cyl•S•π)/4α1

So, m = (B²•N_cyl•S•π)/4α1

m = (0.1²•8•0.12•π)/(4*0.87)

m = 0.00867 Kg

Now, let's calculate the total mass flow rate;

m' = (m*N_rev)/n'

Where;

N_rev is number of revolutions given as 1500 rpm = 1500/60 rev/s = 25 rev/s

n' is the repetitions per circle = 2.

Thus;

m' = (0.00867*25)/2

m' = 0.108375 kg/s

The temperature at state 2 is gotten from the formula;

T2 = T1*r^(k - 1)

Where r is compression ratio.

We know that formula for compression ratio is;

the ratio of the maximum to minimum volume in the cylinder of an internal combustion engine.

In the question, we are told that minimum volume enclosed in the cylinder is 5 percent of the maximum cylinder volume.

Thus,

r = 100/5 = 20

So, T2 = 288*20^(1.4 - 1)

T2 = 954.563 K

The cut off ratio is gotten from the formula;

r_c = α3/α2 = T3/T2

T3 = 2000°C = 2000 + 273K = 2273K

Thus; r_c = 2273/954.563

r_c = 2.38

The heat input is gotten from the formula;

q_in = cp(T3 - T2)

q_in = 1.005(2273 - 954.563)

q_in = 1325.03 KJ/Kg

The efficiency is gotten from;

η = 1 - [1/(r^(k - 1)]*[((r_c)^(k) - 1)/(k(r_c - 1))]

Thus;

η = 1 - [1/(20^(1.4 - 1)]*[((2.38)^(1.4) - 1)/(1.4(2.38 - 1))]

η = 0.63

Now, the power output is gotten from the equation;

W' = m'•η•q_in

W' = 0.108375*0.63*1325.03

W' = 90.47 KW

7 0

3 years ago

A glass plate is subjected to a tensile stress of 40 MPa. If the specific surface energy is 0.3 J/m2 and the modulus of elastici

Pavlova-9 [17]

Answer:

8.24μm

Explanation:

The theory of brittle fracture was used to solve this problem.

And if you follow through with the attachment made a the subject of the formula

Such that,

a = 2x(69x10⁹)x0.3/pi(40x10⁶)²

= 4.14x10¹⁰/5.024x10¹⁵

= 8.24x10^-06

= 8.24μm

This is the the maximum length of the surface flaw

4 0

3 years ago

ANSWER QUICK

luda_lava [24]

Answer:

u will need good car parts and a very well made engine

Explanation:

u need a good engine because if u only work on the outer layer of the car the inner parts will be slow and old and the car will have problems

5 0

3 years ago