Electromagnetic waves can transfer energy without a material medium.
3 examples of elctromagnetic energy include: Radio wave, X-rays and gamma rays
<h3>What is wave?</h3>
A wave is a disturbance that transfers energy from one point to another.
Electromagnetic waves are waves that does not require a material medium for the tranfer of energy
- Radio wave
- Gamma rays
- X-rays
- Light wave
Read more on Electromagnetic waves here: brainly.com/question/13874687
Answer:
12.84 mg/L
Explanation:
We are given;
Volume of lake; V = 1.1 x 10^(6) m³
decay coefficient; K = 0.10/day = 0.1/(24 × 60 × 60) /s = 0.00000115741 /s
Factory rate: Q_f = 4.3 m³/s
Factory concentration: C_f = 100 mg/L
Stream rate: Q_s = 34 m³/s
Stream Concentration: C_s = 2.3 mg/L
Now, to find the steady state concentration of pollutant in the lake, we will use the formula;
(Q_s•C_s) + (Q_f•C_f) = (Q_f + Q_s)C_L + (KV•C_L)
Where C_L is the steady state concentration of pollutant in the lake.
Thus, making C_L the subject, we have;
C_L = [(Q_s•C_s) + (Q_f•C_f)]/(Q_f + Q_s + K•V)
Plugging in the relevant values gives;
C_L = ((34 × 2.3) + (4.3 × 100))/(4.3 + 34 + (0.00000115741 × 1.1 × 10^(6)))
C_L = 12.84 mg/L
Answer:
10.203 Volts
Explanation:
For this problem, we need to understand that a series resistive circuit is simply a circuit with some type of voltage source and some resistors, in this case, R1 and R2.
First, we need to find the voltage in the circuit. To do this, we need to find the total resistance of the circuit. When two resistors are in series, you sum the resistance. So we can say the following:
R_Total = R1 + R2
R_Total = 570 Ω + 560 Ω
R_Total = 1130 Ω
Now that we have R_Total for the circuit, we can find the voltage of the circuit by using Ohm's law, V = IR.
V_Total = I_Total * R_Total
V_Total = 17.9 mA * 1130 Ω
V_Total = 20.227 V
Now that we have V_Total, we can find the voltage drop across each resistor by using Ohm's law once more. Note, that since our circuit is series, both resistors will have the same current (I.e., I_Total = I_1 = I_2).
V_Total = V_1 + V_2
V_Total = V_1 + I_2*R2
V_Total - I_2*R2 = V_1
20.227 V - (17.9 mA * 560 Ω) = V_1
20.227 V - (10.024 V) = V_1
10.203 V = V_1
Hence, the voltage drop across R1 is 10.203 Volts.
Cheers.
Answer:
b. 2.3 kPa.
Explanation:
This situation can be modelled by Bernoulli's Principle, as there are no energy interaction throughout the multisection pipe and current lines exists between both ends. Likewise, this system have no significant change in gravitational potential energy since it is placed horizontally on the ground and is described by the following model:
Where:
, 
- Pressures at the beginning and at the end of the current line, measured in kilopascals.
- Water density, measured in kilograms per cubic meter.
, 
- Fluid velocity at the beginning and at the end of the current line, measured in meters per second.
Now, the pressure difference between these two points is:
If 
, 
and 
, then:
(1 kPa is equivalent to 1000 Pa)
Hence, the right answer is B.
