Explanation:
Diesel cycle:
All diesel engine work on diesel cycle .In diesel cycle there are four process .These processes are as follows
1. Adiabatic reversible compression
2.Heat addition at constant pressure
3.Adiabatic reversible expansion
4.Constant volume heat rejection
In general compression ratio in diesel engine is high as compare to petrol engine.But the efficiency of diesel cycle is less as compare to petrol cycle for same compression ratio.
Applications of diesel cycle:
Generally diesel cycle used for heavy vehicle or equipment because heavy vehicle or equipment is required high initial torque.So this cycle have lots of applications such as in industrial machining,in trucks,power plant,in mining ,in defense or military,large motors ,compressor and pump etc.
Answer:
// Program is written in Java Programming Language
// Comments are used for explanatory purpose
import java.util.*;
public class FlipCoin
{
public static void main(String[] args)
{
// Declare Scanner
Scanner input = new Scanner (System.in);
int flips;
// Prompt to enter number of toss or flips
System.out.print("Number of Flips: ");
flips = input.nextInt();
if (flips > 0)
{
HeadsOrTails();
}
}
}
public static String HeadsOrTails(Random rand)
{
// Simulate the coin tosses.
for (int count = 0; count < flips; count++)
{
rand = new Random();
if (rand.nextInt(2) == 0) {
System.out.println("Tails"); }
else {
System.out.println("Heads"); }
rand = 0;
}
}
Ucsaaaaauxx627384772938282’cc ed un e uff ridicolizzarla +golfista
Answer: Some activities that I do in my daily life that require energy are:
1. Doing ballet
2. Studying
3. Walking up and down stairs
4. Stretching
5. Running on the treadmill
Hope this helps! :)
Explanation:
Answer:
Bore = 7 cm
stroke = 6.36 cm
compression ratio = 10.007
Explanation:
Given data:
Cubic capacity of the engine, V = 245 cc
Clearance volume, v = 27.2 cc
over square-ratio = 1.1
thus,
D/L = 1.1
where,
D is the bore
L is the stroke
Now,
V = 
or
V = 
on substituting the values, we have
245 =
or
D = 7.00 cm
Now,
we have
D/L = 1.1
thus,
L = D/1.1
L = 7/1.1
or
L= 6.36 cm
Now,
the compression ratio is given as:
on substituting the values, we get
or
Compression ratio = 10.007
