Answer:
20, 083 L
Explanation:
The mistake was the result of not using units when converting the 7862 l to Kg. They used the density in pounds hence they multiplied by 1.77 Lb/L and obtained 13597 Lb not Kg as they assumed.
To obtain the amount needed to refuel they subtracted this quantity from the 22,300 Kg required for the trip again obtaining the wrong quantity of 8703 Kg and they converted this to liters by dividing the density to get 4916 L and then placed then 5000 L of fuel
The quantity required was
7862 L * 1.77 Lb/L = 13915.74 Lb (pounds not kilos)
then converting this pounds to Kg by multiplying by 0.454 Kg/L one gets
6173 Kg on board
Amount Required
( 22,300 -6173) : 16127 Kg
16127 Kg/ 0.803 Kg/L = 20083 L
Answer:
Explanation:
Fist you need to identify where the leak is coming from. You can do this by either listening for the leak or spraying soapy water on the exhaust to look for air bubbles coming out of the exhaust. Depending on the spot of the leak there are many ways you can fix this leak.
1. Exhaust clamp
2. Exhaust putty
3. Exhaust tape
4. New exhaust
Exhaust clamp is best used for holes on straight pipes.
Putty is best used on welds or small holes like on exhaust manifolds or welds connecting various pieces like catalytic converters, mufflers, or resonators.
Tape will work best on straight pipes with holes.
New exhaust is for when the thig is beyond repair, like rust.
Now good luck because working on exhausts is a pain.
Answer:
Gravitational force (pulled downward by the Earth)
Normal force (pushed upward by the ground)
Applied force (pushed by the person)
Friction force (pulled opposite the direction of motion by the roughness of the ground)
Answer:
t = 30.1 sec
Explanation:
If the ant is moving at a constant speed, the velocity vector will have the same magnitude at any point, and can be decomposed in two vectors, along directions perpendicular each other.
If we choose these directions coincident with the long edge of the paper, and the other perpendicular to it, the components of the velocity vector, along these axes, can be calculated as the projections of this vector along these axes.
We are only interested in the component of the velocity across the paper, that can be calculated as follows:
vₓ = v* sin θ, where v is the magnitude of the velocity, and θ the angle that forms v with the long edge.
We know that v= 1.3 cm/s, and θ = 61º, so we can find vₓ as follows:
vₓ = 1.3 cm/s * sin 61º = 1.3 cm/s * 0.875 = 1.14 cm/s
Applying the definition of average velocity, we can solve for t:
t =
= 
⇒ t = 30.1 sec
