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Tema [17]
3 years ago
7

Who is the first president of China ?

Physics
2 answers:
Kitty [74]3 years ago
6 0

The President is Xi Jinping

Contact [7]3 years ago
5 0

President  Xi Jinping is the first president of China

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What type of galaxy is this?
stiks02 [169]

Answer:

Barred Spiral.

8 0
2 years ago
Running is probably the simplest individual sport for promoting both health-related and skill-related fitness.
Tamiku [17]

Answer:

Running is probably the simplest individual sport for promoting both health-related and skill-related fitness. Fencing is often referred to as "mental chess" because it requires dexterity, endurance, and discipline. Individual sports require the coach to make all of the decisions for the athlete.

8 0
2 years ago
A block of mass m = 2.0 kg lies on a rough ramp that is inclined at an angle θ = 20oto the horizontal. A force F of magnitude 5.
Marina86 [1]

Answer:

a) 0.64 b) 2.17m/s^2 c) 8.668joules

Explanation:

The block was on the ramp, the ramp was inclined at 20degree. A force of 5N was acting horizontal to the but not parallel to the ramp,

Frictional force = horizontal component of the weight of the block along the ramp + the applied force since the block was just about move

Frictional force = mgsin20o + 5N = 6.71+5N = 11.71

The force of normal = the vertical component of the weight of the block =mgcos20o = 18.44

Coefficient of static friction = 11.71/18.44= 0.64

Remember that g = acceleration due to gravity (9.81m/s^2) and m = mass (2kg)

b) coefficient of kinetic friction = frictional force/ normal force

Fr = 0.4* mgcos 20o = 7.375N

F due to motion = ma = total force - frictional force

Ma = 11.71 - 7.375 = 4.335

a= 4.335/2(mass of the block) = 2.17m/s^2

C) work done = net force *distance = 4.335*2= 8.67Joules

8 0
3 years ago
A hollow cylinder with an inner radius of 4 mm and an outer radius of 25 mm conducts a 4-A current flowing parallel to the axis
ivann1987 [24]

Answer:

2.1 × 10⁻⁵ T

Explanation:

Given:

Inner radius, r = 4 mm = 0.004 m

Outer radius, R = 25 mm = 0.025 m

Current, I = 4 A

Distance of the point from the center, a = 17 mm = 0.017 m

μ₀ = 4π × 10⁻⁷ T·m/A

Now,

For the hollow cylinder magnetic field (B) is given as:

B=\frac{\mu_0 I(a^2-r^2)\textup{}}{2\pi a(R^2-r^2)\textup{}}

on substituting the respective values, we get

B=\frac{4\pi\times10^{-7}\times4(0.017^2-0.004^2)\textup{}}{2\pi\times0.017(0.025^2-0.004^2)\textup{}}

or

B = 2.1 × 10⁻⁵ T

5 0
3 years ago
The frequency of a microwave signal is 9.76 ghz. what is its wavelength? (c = 3.00 × 108 m/s)
dolphi86 [110]
The basic relationship between frequency of an electromagnetic wave and wavelength of the wave is
c = \lambda f
where c=3 \cdot 10^8 m/s is the speed of light.

Manipulating the equation, we can rewrite it as
\lambda =  \frac{c}{f}

The frequency of the wave in our problem is
9.76 GHz = 9.76 \cdot 10^9 Hz
so if we use the previous formula, we find the correspondant wavelength:
\lambda =  \frac{3 \cdot 10^8 m/s}{9.76 \cdot 10^9 Hz} =0.031 m
8 0
3 years ago
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