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malfutka [58]
2 years ago
11

When are theories constructed?

Physics
1 answer:
Fittoniya [83]2 years ago
8 0

Hi, This is the answer...

Theories are constructed <u>after there is numerous data collected during the </u><u>experiment.</u>

Hope it helps you...Pls mark brainliest if it helps you....(by Benjemin)

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A hot-air balloon of diameter 12 mm rises vertically at a constant speed of 14 m/s. A passenger accidentally drops his camera fr
fgiga [73]

Answer:

<em>The balloon is 66.62 m high</em>

Explanation:

<u>Combined Motion </u>

The problem has a combination of constant-speed motion and vertical launch. The hot-air balloon is rising at a constant speed of 14 m/s. When the camera is dropped, it initially has the same speed as the balloon (vo=14 m/s). The camera has an upward movement for some time until it runs out of speed. Then, it falls to the ground. The height of an object that was launched from an initial height yo and speed vo is

\displaystyle y=y_o+v_o\ t-\frac{g\ t^2}{2}

The values are

\displaystyle y_o=15\ m

\displaystyle v_o=14\ m/s

We must find the values of t such that the height of the camera is 0 (when it hits the ground)

\displaystyle y=0

\displaystyle y_o+v_o\ t-\frac{g\ t^2}{2}=0

Multiplying by 2

\displaystyle 2y_o+2v_ot-gt^2=0

Clearing the coefficient of t^2

\displaystyle t^2-\frac{2\ V_o}{g}\ t-\frac{2\ y_o}{g}=0

Plugging in the given values, we reach to a second-degree equation

\displaystyle t^2-2.857t-3.061=0

The equation has two roots, but we only keep the positive root

\displaystyle \boxed {t=3.69\ s}

Once we know the time of flight of the camera, we use it to know the height of the balloon. The balloon has a constant speed vr and it already was 15 m high, thus the new height is

\displaystyle Y_r=15+V_r.t

\displaystyle Y_r=15+14\times3.69

\displaystyle \boxed{Y_r=66.62\ m}

3 0
2 years ago
At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball
Ymorist [56]

Answer:440.03 N

Explanation:

Given

horizontal component of acceleration (a_x)=800 m/s^2

vertical component of acceleration (a_y)=880 m/s^2

mass of ball =0.37 kg

Force in horizontal direction=m\times a_x=0.37\times 800=296 N

Force in vertical direction =m\times a_y=0.37\times 880=325.6 N

Therefore net force is

F=F_x+F_y

|F|=\sqrt{296^2+325.6^2}

|F|=440.03 N

5 0
3 years ago
What is the heart rate recorded a few minutes after completing a workout?
DochEvi [55]
Correct answer should be C
8 0
3 years ago
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a ladybug sits at the outer edge of a merry-go-round and a gentleman bug sits halfway between her and the axis of rotation. The
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The gentleman bug's angular speed is the same as the ladybug's (1 rev/s)
6 0
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Why is it useful to calculate average speed?
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When you are driving
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