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Masja [62]
2 years ago
6

What is your displacement if you travel 5 miles north to the store

Physics
1 answer:
kumpel [21]2 years ago
3 0

Answer:

5miles North

Explanation:

The displacement to the store is 5miles northward.

Displacement is the distance traveled in a specific direction. Displacement is a vector quantity.

A vector has both magnitude and direction.

The magnitude is the amount of that quantity

The direction is its orientation from a reference.

 Therefore, the displacement is 5miles north

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The space shuttle, in circular orbit around the Earth, collides with a small asteroid which ends up in the shuttle's storage bay
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Answer:

b

Explanation:

The space shuttle, in circular orbit around the Earth, collides with a small asteroid which ends up in the shuttle's storage bay.

This form of collision is called inelastic collision. And inelastic collision momentum is conserved but the kinetic energy is not conserved. Hence the correct option is b. only momentum is conserved.

 

8 0
3 years ago
After pushing away from each other, two objects have equal but opposite momentum. Which of the following is true for the total m
weqwewe [10]
I think the answer is B
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Water, H2O, is made up of different elements, hydrogen and oxygen. Is this type of combination a mixture or a pure substance? A)
strojnjashka [21]

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3 years ago
Read 2 more answers
Two circus performers rehearse a trick in which a ball and a dart collide. Horatio stands on a platform 9.8 m above the ground a
xenn [34]

Answer:

Time = 0.55 s

Height = 8.3 m

Explanation:

The ball is dropped and therefore has an initial velocity of 0. Its acceleration, g, is directed downward in the same direction as its displacement, h_b.

The dart is thrown up in which case acceleration, g, acts downward in an opposite direction to its displacement, h_d. Both collide after travelling for a time period, t. Let the height of the dart from the ground at collision be h_d and the distance travelled by the ball measured from the top be h_b.

It follows that h_d+h_b=9.8.

Applying the equation of motion to each body (h = v_0t + 0.5at^2),

Ball:

h_b=0\times t + 0.5\times 9.8t^2 (since v_{b0} =0.)

h_b=4.9t^2

Dart:

h_d=17.8\times t - 0.5\times9.8t^2 (the acceleration is opposite to the displacement, hence the negative sign)

h_d=17.8\times t - 4.9t^2

But

h_b+h_d =9.8

17.8\times t - 4.9t^2+4.9t^2 =9.8

17.8\times t = 9.8

t = 0.55

The height of the collision is the height of the dart above the ground, h_d.

h_d=17.8\times t - 4.9t^2

h_d=17.8\times 0.55 - 4.9\times(0.55)^2

h_d=9.79 - 1.48225

h_d=8.3

8 0
3 years ago
Three monkeys A, B, and C weighing 20, 26, and 25 lb, respectively, are climbing up and down the rope suspended from D. At the i
Marina86 [1]

Answer:2235.2lb-ft/s^2

Explanation:

Given

Mass of monkey A=20lb

Mass of monkey B=26lb

Mass of monkey C=25lb

acceleration of monkey A=4.2ft/s^2

acceleration of monkey B=0

acceleration of monkey C=-5.4ft/s^2

Force Due to monkey A\left ( F_A\right )=20\times 4.2 =84lb-ft/s^2\left ( downwards\right )

Force Due to monkey A\left ( F_B\right )=26\times 0 =0lb-ft/s^2

Force Due to monkey A\left ( F_C\right )=25\times 5.4 =135 lb-ft/s^2\left ( upward\right )

In addition to it  Weights of monkeys will be acting downwards therefore net Downwards force is balanced by tension

T=\left ( 20+26+25\right )32.2+84-135=2235.2 lb-ft/s^2

5 0
3 years ago
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