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zloy xaker [14]
2 years ago
5

You are watching a television show about Navy pilots. The narrator says that when a Navy jet takes off, it accelerates because t

he engines are at full throttle and because there is a catapult that propels the jet forward. You begin to wonder how much force is supplied by the catapult. You look on the Web and find that the flight deck of an aircraft carrier is about 90.0 m long, that an F-14 has a mass of 24800 kg, that each of the two engines supplies 27000 lb of thrust, and that the takeoff speed of such a plane is about 158 mi/h. Estimate the average force on the jet due to the catapult.
Physics
1 answer:
zepelin [54]2 years ago
6 0

You are watching a television show about Navy pilots. The narrator says that when a Navy jet takes off, the average force on the jet is due to the catapult is mathematically given as

What is the average force on the jet is due to the catapult?

Generally, the equation for acceleration is mathematically given as

a=\frac{vf^2-vi^2}{2s}\\\\\Therefore\\\\a=\frac{69.29^2-0^2}{2(90}\\\\a=26.673m/s^2

In conclusion, The force

F=m*a

F=15100*26.673

F=40272.3N

F 402 KN

Read more about force

brainly.com/question/13191643

#SPJ1

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Answer:

3.95241\times 10^{21}\ Photons/second

Explanation:

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Power output of Sun

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I=\frac{P}{4\pi d^2}\times A\\\Rightarrow I=\frac{3.83\times 10^{26}}{4\pi (1.5\times 10^{11})^2}\times 1\\\Rightarrow I=1354.5854\ W

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E=\frac{hc}{\lambda}\\\Rightarrow E=\frac{6.626\times 10^{-34}\times 3\times 10^8}{580\times 10^{-9}}\\\Rightarrow E=3.42724\times 10^{-19}\ J

Number of photons

N=\frac{I}{E}\\\Rightarrow N=\frac{1354.5854}{3.42724\times 10^{-19}}\\\Rightarrow N=3.95241\times 10^{21}\ Photons/second

The number of photons are 3.95241\times 10^{21}\ Photons/second

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