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Galina-37 [17]
3 years ago
14

What is a robin is it a herbivores or carnivores or omnivores or decompers

Physics
1 answer:
Arlecino [84]3 years ago
8 0
A robin is a small carnivore bird which feed on insects, earthworms, spiders and bees. It needs about 60 calories per day from these organisms. This bird has a short lifespan of only 7 years. Hope this answers the question. Have a nice day.
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An electron moving parallel to a uniform electric field increases its speed from 2.0 × 10^7 m/s to 4.0 × 10^7 m/s over a distanc
julia-pushkina [17]

Answer:

E = 2.84 * 10^5 N/C

Explanation:

The speed increased from 2.0 * 10^7 m/s to 4.0 * 10^7 m/s over a 1.2 cm distance.

Let us find the acceleration:

v^2 = u^2 + 2as

(4.0 * 10^7)^2 = (2.0 * 10^7)^2 + 2 * a * 0.012\\\\(4.0 * 10^7)^2 - (2.0 * 10^7)^2 = 0.024a\\\\1.2 * 10^{15}= 0.024a\\\\a = 1.2 * 10^{15} / 0.024\\\\a = 5 * 10^{16} m/s^2

Electric force is given as the product of charge and electric field strength:

F = qE

where q = electric charge

E = Electric field strength

Force is generally given as:

F = ma

where m = mass

a = acceleration

Equating both:

ma = qE

E = ma / q

For an electron:

m = 9.11 × 10^{-31} kg

q = 1.602 × 10^{-19} C

Therefore, the electric field strength of the electron is:

E = \frac{9.11 * 10^{-31} * 5 * 10^{16}}{1.602 * 10^{-19}} \\\\E = 2.84 * 10^5 N/C

8 0
3 years ago
Find the configuration of any tow​
Yuki888 [10]

Answer:

<h2>Ok I choose Copper and Zinc , Here is your answer⤴️⤴️</h2><h3>Hope it's helpful for you mark me as brainlist please</h3>

6 0
3 years ago
If a 12 kg cat is sitting 5 m up in a tree, how much PE does it have?
Helen [10]

Answer:

588 J

Explanation:

PE (potential energy) = (mass) x (gravity) x (height)

mass = 12 kg

gravity = 9.8m/s^2

height = 5 m

PE = (12) x (9.8) x (5) = 588 J (Joules)

5 0
2 years ago
Find the separation of two points on the Moon’s surface that can just be resolved by the 200 in. (= 5.1 m) telescope at Mount Pa
rewona [7]

Answer:

The separation of the 2 points should be 50.0 meters.

Explanation:

According to Rayleigh's scattering criteria the angular separation between 2 points to be resolved equals

\theta =1.22\cdot \frac{\lambda }{D}

Applying the given values we get

\theta =1.22\cdot \frac{550\times 10^{-9} }{5.1}=0.1316\times 10^{-6}rads

thus the linear separation equals L=\theta \times Distance

Applying the given values we get

L=0.1316\times 10^{-6} \times 3.8\times 10^{5}\times 10^{3}meters\\\\\therefore L=50.00metes

6 0
3 years ago
A particle has a charge of +1.5 µC and moves from point A to point B, a distance of 0.15 m. The particle experiences a constant
kirill [66]

Answer:

Part a)

F = 6 \times 10^{-3} N

Direction of force is along the motion of charge

Part b)

E = 4000 N/C

direction of electric field is along the direction of motion

Explanation:

Part a)

As we know that the change in electric potential energy is equal to the work done by electric field

W = EPE_A - EPE_B

W = 9.0 \times 10^{-4} J

now from the equation of work done we know that

W = F.d

(9.0 \times 10^{-4}) = F(0.15)

F = 6 \times 10^{-3} N

Direction of force is along the motion of charge

Part b)

As we know the relation between electrostatic force and electric field given as

F = qE

(6 \times 10^{-3}) = 1.5 \times 10^{-6} E

E = 4000 N/C

direction of electric field is along the direction of motion

8 0
3 years ago
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